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noname [10]
3 years ago
7

What is an effective method for separating a mixture of alcohol and water? A. . mixing the ingredients B. . distillation C. evap

oration D. magnetism
Chemistry
2 answers:
Airida [17]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

A process in which liquid mixture is separated by selective boiling and condensation is known as distillation process.

It is known that boiling point of alcohols is low therefore, when a mixture of alcohol and water is boiled then alcohol will evaporate from the mixture and the water will remain as the liquid.

Therefore, the distillation column will collect the vapors of alcohol separately and hence, it can be separated from water.

Thus, we can conclude that distillation is an effective method for separating a mixture of alcohol and water.

Nataly [62]3 years ago
7 0
<span>The  effective method for separating a mixture of alcohol and water is the
Distillation
</span> By this you only get about 70% alcohol 30% water
As  they are  <span>azeotropes and cannot be distilled further
so correct option is B
hope it helps
</span><span>, </span>
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A scientist is tracking an object orbiting the sun that is found between mars and Jupiter. Which additional feature can be used
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Size is the additional feature that determines asteroids.

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4 0
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Answer:

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Explanation:

There are 3 substituents, 1 chlorine, 1 bromine, and 1 methyl group.

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1 year ago
What is the total number of sulfur atoms in 5caso4
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A pot of water is heated over a fire, and then frozen peas are added to the hot water. What happens to the energy in this situat
ZanzabumX [31]

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Identify the limiting reactant when 1.22 g of O2 reacts with 1.05 g H2 to produce water.
kupik [55]
The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,

                    2H2 + O2 --> 2H2O

The masses of each of the reactants are calculated below.

          2H2 = 4(1.01 g) = 4.04 g
          O2 = 2(16 g) = 32 g

Given 1.22 grams of oxygen, we determine the mass of hydrogen needed.
        (1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2

Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.


<em>Answer: 1.22 g of oxygen</em>
4 0
3 years ago
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