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noname [10]
3 years ago
7

What is an effective method for separating a mixture of alcohol and water? A. . mixing the ingredients B. . distillation C. evap

oration D. magnetism
Chemistry
2 answers:
Airida [17]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

A process in which liquid mixture is separated by selective boiling and condensation is known as distillation process.

It is known that boiling point of alcohols is low therefore, when a mixture of alcohol and water is boiled then alcohol will evaporate from the mixture and the water will remain as the liquid.

Therefore, the distillation column will collect the vapors of alcohol separately and hence, it can be separated from water.

Thus, we can conclude that distillation is an effective method for separating a mixture of alcohol and water.

Nataly [62]3 years ago
7 0
<span>The  effective method for separating a mixture of alcohol and water is the
Distillation
</span> By this you only get about 70% alcohol 30% water
As  they are  <span>azeotropes and cannot be distilled further
so correct option is B
hope it helps
</span><span>, </span>
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Tollens’ test, also known as silver-mirror test, is a qualitative laboratory test used to distinguish between an aldehyde and a
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Explanation:

Tollens' reagent is prepared by using two-step process : -

Step 1:

Silver oxide is formed by mixing aqueous silver nitrate with base like sodium hydroxide. The reaction is shown below as:

AgNO_3 + NaOH &\rightarrow AgOH + NHO_3 \nonumber \\ 2AgOH &\rightarrow Ag_2O + H_2O

Step 2

Ammonia solution is drop-wise added until all the silver oxide dissolves to form the reagent. The reaction is shown below as:

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3 0
3 years ago
What is the element presented, in this compound?
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compound name compound formula elements present

water H2O hydrogen (H) and oxygen (O)

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carbon monoxide CO carbon (C) and oxygen (O)

carbon dioxide CO2 carbon (C) and oxygen (O)

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5 0
2 years ago
The pH of a 0.29 M solution of carbonic acid (H2CO3) is measured to be 3.44. Calculate the acid dissociation constant Ka of carb
arsen [322]

Answer: 4.55x10^-7

Explanation:

H2CO3 + H20 <==> H3O+ + HCO3-

Desigining an ICE table, we have:

Initial conc. of H2CO3 = 0.29 M

Initial conc. of H3O+ = 0

Initial conc. of HCO3- = 0

Change in conc. of H2CO3 = - x

Change in conc. of H3O+ = x

Change in conc. of HCO3- = x

Equilibrium conc. of H2CO3 = 0.29 - x

Equilibrium conc. of H3O+ = x

Equilibrium conc. of HCO3- = x

but pH = 3.44

pH = - log[H30+]

[H30+] = 10^-3.44 = 3.63x10^-4

[H30+] = 3.63x10^-4

Ka = [H3O+].[HCO3-] / [H2CO3]

[H30+] = x = 3.63x10^-4

[HCO3-] = 3.63x10^-4

[H2CO3] = 0.29 - x = 0.29 - 3.63x10^-4 = 0.289637

Ka = (3.63x10^-4)(3.63x10^-4)/0.289637 = 4.55x10^-7

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