How many grams are in 6.02 x 10^23 molecules of glucose C6H12O6?

Chemistry

2 answers:

astra-53 [7]3 years ago

4 0

198 g of Glucose Is the answer.

musickatia [10]3 years ago

3 0

180 grams the way to calculate this is to know the molar mass of each of the elements C6 means there are 6 carbon atoms carbons molar mass is 12 grams so 12*6=72grams of carbon. Hydrogens molar mass is 1 gram so 12 hydrogen atoms 12 grams. Oxygens molar mass is 16 grams so 16*6=96 grams add it all together gives molar mass. Molar mass is grams when using avogadros number you need to know elements atomic mass and have periodic table handy for these sorts of questions. Molar mass of an element is atomic mass only difference being one is in grams other in tiny atomic units.

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natulia [17]

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3 years ago

Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c

malfutka [58]

Answer:

$[F^-]_{max}=4x10{-3}\frac{molF^-}{L}$

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

$Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)$

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

$[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}} \\$