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Flauer [41]
2 years ago
15

Please help!!!!!!!!!!!!!!!!!

Physics
1 answer:
Roman55 [17]2 years ago
3 0

Answer:

I feel like it is C

Explanation:

I think it is C because it involves plant, which is a form of life and it involves the amount of water being given to the plants.

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The rectangular coils in a 345-turn generator are 12 cm by 12 cm. Part A
Likurg_2 [28]

Answer:

118.166 volt

Explanation:

We have given number of turns N =345

Sides of the rectangular coils is 12 cm =0.12 m

So area A =0.12×0.12=0.0144 m^2

Magnetic field B =0.45 T

Angular speed =505 rpm

Speed in rad/sec \omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 505}{60}=52.8566rad/sec

The emf is given by E=NAB\omega SIN\omega t

For maximum emf sinwt =1

So E=345\times 0.0144\times 0.45\times 52.8566=118.166volt

4 0
3 years ago
Two blocks are connected as shown in the diagram below. Assume that the ramp is frictionless. Draw the force diagram for the blo
cluponka [151]

Answer:

diagram: see image, x-component: 84.3 N, acceleration: 4.38 m/s^2

Explanation:

(see image for further explanation)

5 0
3 years ago
Which of the following is NOT a step in the technical design<br> process?
dalvyx [7]

Answer:

incurriculum design process the answer is designs

4 0
2 years ago
A plane wave with a wavelength of 500 nm is incident normally ona single slit with a width of 5.0 × 10–6 m.Consider waves that r
kaheart [24]

To solve this exercise it is necessary to use the concepts related to Difference in Phase.

The Difference in phase is given by

\Phi = \frac{2\pi \delta}{\lambda}

Where

\delta = Horizontal distance between two points

\lambda = Wavelength

From our values we have,

\lambda = 500nm = 5*10^{-6}m

\theta = 1\°

The horizontal distance between this two points would be given for

\delta = dsin\theta

Therefore using the equation we have

\Phi = \frac{2\pi \delta}{\lambda}

\Phi = \frac{2\pi(dsin\theta)}{\lambda}

\Phi = \frac{2\pi(5*!0^{-6}sin(1))}{500*10^{-9}}

\Phi= 1.096 rad \approx = 1.1 rad

Therefore the correct answer is C.

6 0
3 years ago
When a rubber band is pulled back on your finger but not yet let go how is that potential energy?
loris [4]
It is potential energy because the band is not in movement, th band has the potential to move.
4 0
3 years ago
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