Force M2 exerts on tension T
T = M2 g
T = M1 g sin theta - M1 g u cos theta
Note that M1 g is exerted down the plane while the frictional force opposes this motion and will be directed in the opposite direction of M1 g
M2 g = M1 g sin theta - u M1 g cos theta
1 = 2 sin 36 - u 2 cos 36
.5 = sin 36 - u cos 36
u = (sin 36 - .5) / cos 36 = .108
Any friction less that this will result in sliding
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Answer:
the acceleration is constant
Explanation:
When stone is moving in the air then it has force of gravity on it
Since there is no other force like air friction is to be neglected
so we know that
so we will have
so the acceleration of the stone is always constant and directed vertically downwards with constant magnitude
Answer:
Both Particles having a positive charge.
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Answer:
A
Explanation:
Finding the (maximum) respective prime powers would yield the answer. Also we need not ... Is perfectly divisible by 720^n? ... So we can say that for any positive value of n it not divisible.