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Maru [420]
3 years ago
14

Two identical arrows, one with twice the speed of the other, are fired into a bale of hay. Assuming the hay exerts a constant fr

ictional force on the arrows, the faster arrow will penetrate how much farther than the slower arrow? EXPLAIN
Physics
1 answer:
satela [25.4K]3 years ago
3 0

Explanation:

When there is frictional force distance traveled by the arrow is s = (v^2)/(2μ_kg)

v= velocity of the object

μ_k = kinetic friction coefficient

g= acc. due to gravity.

as distance is proportional to square of the speed therefore the faster arrow penetrate a distance 4 times the distance penetrate by slower arrow.

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The area around a charged object that can exert a force on other charged objects is an electric ___
Ymorist [56]
Answer is:

Electric field.
8 0
3 years ago
What does deposition mean in a sedimentary formation
Zinaida [17]
Answer:

Sedimentary rocks are types of rock that are formed by the deposition and subsequent cementation of that material at the Earth's surface and within bodies of water. Deposition means that all the sediments, soil, and rocks are all compressed (tightly pressed into each other) and create sedimentary rocks.

I hope this helps! :)
4 0
3 years ago
( Can someone help? )
Murrr4er [49]

Answer:

Answer would be 0.33

Explanation:

Calculations

8 0
3 years ago
Read 2 more answers
A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o
Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m

The fundamental frequency of the wire is given by

f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N

The tension in the wire is 67.9064 N

7 0
3 years ago
You and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for
anzhelika [568]

Answer:

60 N.C

Explanation:

The box will move in the direction of the push and pull with a force of 60 N. C.

7 0
3 years ago
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