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Sidana [21]
4 years ago
5

Which of the following best describes good autobiographies?

Chemistry
2 answers:
Nuetrik [128]3 years ago
5 0
Revealing, because you learn new, and hopefully, interesting things about the author.
lesya692 [45]3 years ago
4 0
A. revealing  because an autobiography is when you write about you and your personal life
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Henri becquerel and the curies found out that _____.
natulia [17]

Henri becquerel and the curies found out that atoms were not indivisible and indestructible

Explanation:

The French Physicist, Henri Becquerel, created the appearance of radioactivity. He shared the Nobel Prize in Physics with Marie Curie and Pierre Curie (Marie's husband) in 1903 for their work in radiation. A radionuclide will emit transmission through the process of radioactive sense.

5 0
4 years ago
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What will the outcome of putting litumus paper into distilled water
Kay [80]
If it is blue litmus paper, it will remain blue. If it is red litmus paper, it will remain red. Water is neither an acid nor a base so it will not change the litmus paper.
5 0
4 years ago
When you mix copper sulphate solution and steel wool, what is the chemical property that can be observed.
bazaltina [42]

Answer:

Explanation:

depending on the activity series there will probably be a single replacement reaction  possibly heat or color change and the copper precipitate out of solution

6 0
3 years ago
What does the symbol Pt mean in a chemical equation in chemistry?
uysha [10]

Explanation:

It is mean Platinum .

hope to helped.

5 0
4 years ago
Hydrogen 3 has a half life of 12.32 years a sample of h-3 weighing 3.02 grams is left for 15.0 years what will the final weight
yawa3891 [41]

Answer:

The final mass of sample is 1.3 g.

Explanation:

Given data:

Half life of H-3 = 12.32 years

Amount left for 15.0 years = 3.02 g

Final amount = ?

Solution:

First all we will calculate the decay constant.

t₁/₂ = ln² /k

t₁/₂ =12.32 years

12.32 y =  ln² /k

k = ln²/12.32 y

k = 0.05626 y⁻¹

Now we will find the original amount:

ln (A°/A) = Kt

ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y

ln (3.02 g/ A) = 0.8439

3.02 g/ A = e⁰°⁸⁴³⁹

3.02 g/ A = 2.33

A = 3.02 g/ 2.33

A = 1.3 g

The final mass of sample is 1.3 g.

8 0
3 years ago
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