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3 years ago

A star with a large luminosity would have a relatively _____ absolute magnitude.

1 answer:

3 0

A star with large luminosity would have a relatively low absolute magnitude. Absolute magnitude is a number that tells how bright a star is from the Earth. However, this scale is backwards and logarithmic, so having a large absolute magnitude value means that the star is faint.

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Nodes give a vertebrate’s back flexibility.<br> A. True<br> B. False

Lapatulllka [165]

No B. its false<span> they do not. Lyphnodes are a permant part of the body and you have them in your Neck</span>

5 0

3 years ago

Read 2 more answers

A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7.5 m off the ground. T

slamgirl [31]

Answer:

$u=14.48m/s$

Explanation:

From the question we are told that:

Height of window $h=2m$

Height of window off the ground $h_g=7.5m$

Time to fall and drop $t=1.3s$

Generally the Newton's equation motion is mathematically given by

$s=ut+\frac{1}{2}at^2$

Where

$h=ut+\frac{1}{2}at^2$

$2=u1.3-\frac{1}{2}*9.8*1.3^2$

$2=u1.3-8.281$

$u=7.91m/s^2$

Generally the Newton's equation motion is mathematically given by

$2as=v^2-u^2$

Where

$-2gh_g=v^2-u^2$

$-2*9.8*7.5=(7.91)^2-u^2$

$-147=62.5681-u^2$

$u=\sqrt{209.5681}$

$u=14.48m/s$

Therefore the ball’s initial speed

$u=14.48m/s$

8 0

3 years ago

Which of these is an example of projectile motion?

Usimov [2.4K]

Answer:

the answer is d I'm pretty sure

8 0

3 years ago

How are electrons represented in orbitals?

Alexxx [7]

Electrons move in atomic orbitals (or subshells). there are four different orbital shapes (s p d f). in each shell, the s subshell is at a lower energy than the p. an orbital diagram is used to determine an atom's electron configurations

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3 years ago

a bat experts a 120 N force on a 0.134 kg baseball for 0.04 seconds. what impolse is excerted on the bat

musickatia [10]

The impulse exerted by a force F on an object in a time $\Delta t$ is given by
$I = F \Delta t$
In our problem, we have a force of 120 N: F=120 N, applied to the baseball for a time of $\Delta t=0.04 s$ . Therefore the impulse is
$I=F \Delta t = (120 N)(0.04 s)=4.8 Ns$

3 0

4 years ago