Answer:
106.24 kJ.
Explanation:
Given that,
Mass of sample of sand, m = 8 kg
Specific heat of sand, c = 664 J/kg-°C
The temperature changes from 20° C to 40° C. We need to find the change in thermal energy. It is given by :

So, the change in thermal energy is 106.24 kJ.
λ = c : f
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.86 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.86
E = 1.896 x 10⁻³³ J
λ = 3 x 10⁸ : 1.011 x 10⁸
λ = 2.97 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.97
E = 1.97 x 10⁻³³ J
λ = 3 x 10⁸ : 1.05 x 10⁸
λ = 2.96 m
E = hf
h = Planck's constant (6.626.10⁻³⁴ Js)
E = 6.626.10⁻³⁴ x 2.96
E = 1.96 x 10⁻³³ J
The covering on the outside of certain animals is the exoskeleton
Answer:
The density of the fluid is 1100 kg/m³.
Explanation:
Given that,
Height = 5.00 cm
Pressure at top =594 Pa
Pressure at bottom = 1133 Pa
We need to calculate the change in pressure
Using formula of change in pressure

Where,
= Pressure at bottom
= Pressure at top
put the value into the formula


Using formula of pressure for density


Where,
= density
P = pressure
h = height
Put the value in to the formula


Hence, The density of the fluid is 1100 kg/m³.
Velocity and speed of a moving body become identical when it tends to move in a straight line.