1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena-14-01-66 [18.8K]
3 years ago
13

What is the heat flux (W/m^2), due to radiation heat transfer, from a black body if the surface temperature is 1000C? The convec

tion heat transfer coefficient is 55 W/(m^2 C).
Physics
2 answers:
12345 [234]3 years ago
7 0

Answer:

55000 W/m²

Explanation:

Parameters given:

Surface temperature, T = 1000°C

Hear transfer coefficient, h = 55 W/m²C

Convection heat transfer coefficient is given as:

h = Heat flux/Temperature

Hence, Heat Flux, q, is given as:

q = h * T

q = 55 * 1000 = 55000 W/m²C

zepelin [54]3 years ago
6 0

Answer:

55000 W/m²

Explanation:

Using

ψ = Hf/θ.................... Equation 1

Where Ψ = convection heat transfer, Hf = heat flux, θ = Surface Temperature

Make Hf the subject of the equation,

Hf = ψθ.................. Equation 2

Given: Ψ = 55 W/m².°C, θ = 1000°C

Substitute into equation 2

Hf = 55(1000)

Hf = 55000 W/m²

Hence the heat flux due to radiation = 55000 W/m²

You might be interested in
A car battery seems to be malfunctioning (not providing the proper voltage and current to start your car). While the car is off
Stella [2.4K]

No. You cannot rule out the battery even after the open circuit voltage measurement. The open-circuit voltage may not have changed but the battery's internal resistance may have greatly increased.

4 0
3 years ago
How did scientists discover the Earth had a liquid outer core and solid inner core?
viktelen [127]
Dr. Inge discovered the make up of the earths inner core by studying how an earthquakes waves bounced off the core. And Inge Lehmann was studying the waves of a 1929 earthquake when she found them acting inconsistently with solid mantle crust 
hope it helps you


6 0
4 years ago
A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
Evgen [1.6K]

Answer:

\dfrac{d\theta}{dt}=0.038\ rad/s

Explanation:

Given that

\dfrac{dx}{dt}= -1\ m/s

From the diagram

tan\theta=\dfrac{21}{x}

By differentiating with time t

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

When x= 10 m

tan\theta=\dfrac{21}{10}

θ = 64.53°

Now by putting the value in equation

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)

\dfrac{d\theta}{dt}=0.038\ rad/s

Therefore rate of change in the angle is 0.038\ rad/s

8 0
3 years ago
Ask Your Teacher Suppose the roller coaster below(h1 = 36 m, h2 = 13 m, h3 = 30) passes point A with a speed of 1.00 m/s. If the
Oliga [24]

Answer:

The answer to the question is

The roller coaster will reach point B with a speed of 14.72 m/s

Explanation:

Considering both kinetic energy KE = 1/2×m×v² and potential energy PE = m×g×h

Where m = mass

g = acceleration due to gravity = 9.81 m/s²

h = starting height of the roller coaster

we have the given variables

h₁ = 36 m,

h₂ = 13 m,

h₃ = 30 m

v₁ = 1.00 m/s

Total energy at point 1 = 0.5·m·v₁² + m·g·h₁

= 0.5 m×1² + m×9.81×36

=353.66·m

Total energy at point 2 = 0.5·m·v₂² + m·g·h₂

= 0.5×m×v₂² + 9.81 × 13 × m = 0.5·m·v₂² + 127.53·m

The total energy at 1 and 2 are not equal due to the frictional force which must be considered

Total energy at point 2 = Total energy at point 1 + work done against friction

Friction work = F×d×cosθ = (\frac{1}{5} × mg)×60×cos 180 = -117.72m

0.5·m·v₂² + 127.53·m = 353.66·m -117.72m

0.5·m·v₂² = 108.41×m

v₂² = 216.82

v₂  =  14.72 m/s

The roller coaster will reach point B with a speed of 14.72 m/s

8 0
3 years ago
This is a change in the position of a body with respect to time relative to a reference point.
dusya [7]

Answer: MOTION

Explanation:

motion is defined as the displacement of an object with respect to time relative to a stationary object (reference point). A good example of an object that can serve as a reference point includes: a tree or a building. The movement of a body at constant speed towards a particular direction at regular intervals of time can be determined and it's called uniform motion.

There are different types of motion, these includes: simple harmonic motion,

linear motion,

circular motion,

Brownian motion,

Rotatory motion

5 0
3 years ago
Read 2 more answers
Other questions:
  • How has the use of computer and advance in technology changed healthcare industry
    13·1 answer
  • A sailboat travels a distance of 600 m in 40 seconds. What speed is it going?
    5·1 answer
  • A model rocket is launched straight upward with an initial speed of 57.0 m/s. It accelerates with a constant upward acceleration
    14·1 answer
  • The free body diagram represents Silly Sally hanging from a trapeze bar. Sally weighs 660 Newtons. What is the force in each of
    12·1 answer
  • A negative body image can affect your fitness because being healthy asks you to keep
    7·1 answer
  • Please answer 11-13. say if i'm right for 10 if you can.
    11·1 answer
  • Why is your physical and mental health important?
    13·2 answers
  • Can someone help me with this question please picture is above
    15·1 answer
  • I need 4 answers for Earth's layers and 4 answers for the Descriptions for Earth's layers graphic organizer.
    13·1 answer
  • 21
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!