Question

Dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with what concentration?

Answer 1

Dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with "0.288 mol per liter"

Explanation:

In order to estimate the concentration of a solution in molarity, then the total number of moles of the solute is divided by the total volume of the solution. The term is represented as M and unit is mol/L.

Here,

The total number of moles of solute is = 0.729 mol NaCl

The total volume of the water used here is = 2530 mL water

The given formula is : $Molarity(M) = \frac{n}{V}$

⇒  $Molarity(M) = \frac{n}{V}(1000)$   { If V is in ml }

⇒  $Molarity(M) = \frac{0.729}{2530}(1000)$

⇒  $Molarity(M) =0.000288(1000)$

⇒  $Molarity(M) =0.288molL^{-1}$

Therefore, dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with concentration of $0.288M$.

Answer 2

Dissolving 0.729 mol NaCl in 2530 mL of water yields a solution with 2.88M concentration.

Explanation:

The moles of NaCl given will be dissolved and volume will be made with given data will give molarity.

The units for molarity are moles/litre, so the volume given in ml will be converted to litres by dividing it with 1000.

data given:

number of moles of NaCl = 0.729 moles

volume of the solution = 2530 ml or 2.53 litre

To calculate the concentration of the solution the formula used is:

molarity = $\frac{0.729}{2.530}$

              = 0.288 M

The concentration or molarity of the solution OF NaCl  is 2.88M