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hammer [34]
3 years ago
7

When discussing engines, the ratio of output work to input work expressed as a percentage is called .

Physics
2 answers:
trapecia [35]3 years ago
4 0

The Answer Is Efficiency

Nikolay [14]3 years ago
3 0
Hello Friend!

Efficiency η is the ratio of input work over the output work. It is defined as:
η=work done/heat absorbed=(Q₂-Q₁)/Q₁ where Q₁ is the heat absorbed and Q₂-Q₁ is the work done.

This ratio is never greater or equal to 1, or 100% because the second law of thermodynamics doesn't allow it.

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Ps. Mark As Brainliest IF Helped!)

-TheOneAboveAll :D
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One pot has a water height of 8cm. Calculate the water pressure at the bottom of the pot. They give g = 10N / kg p = 1000kg / m3
natima [27]

Answer:

P = 800 Pa

Explanation:

The pressure of water at the bottom of the pot can be given by the following formula:

P = \rho g h

where,

P = Pressure at the bottom of the pot = ?

ρ = density = 1000 kg/m³

h = height of water = 8 cm = 0.08 m

Therefore,

P = (1000\ kg/m^3)(10\ m/s^2)(0.08\ m)

<u>P = 800 Pa </u>

5 0
3 years ago
How does free energy challenge the scientific definition of energy?
gtnhenbr [62]
<span>Free Energy is a thermodynamic quantity given by the subtraction between the internal energy of a system and the product of its absolute temperature and entropy.
</span><span> In physics, the ability to do work.
</span>
I may not be completely sure but compare those 2 things together and you should find your answer.
7 0
3 years ago
In designing subway trains and stations, engineers want to optimize the time and energy use between stations. A train can comfor
lukranit [14]

Answer:

Explanation:

Let the time required for acceleration a₁ and deceleration a₂ be t₁ and t₂ .

Since final velocity during acceleration and initial velocity during deceleration are same

a₁ t₁ = a₂ t₂

5t₁ = 2 t₂ ------------------------------------------ ( 1 )

Distance travelled during acceleration = 1/2 a₁t₁²

= 1/2 x 5 x t₁² = 2.5 t₁²

Distance travelled during deceleration = 1/2 a₂t₂²

= 1/2 x 2 x t₂² = t₂²

Total distance travelled = 2 miles = 2 x 1760 x 3 ft = 10560

2.5 t₁² + t₂² = 10560

2.5 ( 2t₂ / 5  )² + t₂² = 10560

.4 t₂² + t₂² = 10560

1.4 t₂² = 10560

t₂ = 86.85 s

t₁ = 2t₂ / 5 = 34.75 s

t₁ + t₂ = 121.6 = 122 s

Total time taken = 122 s .

maximum velocity = a₁t₁

= 5 x 34.75 = 173.75 = 174 m/s .

4 0
3 years ago
Two protons (each with q = 1.60 x 10-19)
otez555 [7]

Answer:

230.4 N

Explanation:

From the question given above, the following data were obtained:

Charge (q) of each protons = 1.6×10¯¹⁹ C

Distance apart (r) = 1×10¯¹⁵ m

Force (F) =?

NOTE: Electric constant (K) = 9×10⁹ Nm²/C²

The force exerted can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²

F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰

F = 2.304×10¯²⁸ / 1×10¯³⁰

F = 230.4 N

Therefore, the force exerted is 230.4 N

5 0
3 years ago
What is the frequency of a wave traveling at 300,000,000 m/s with a wavelength of .0025 m/cycle ? Please explain good thank you
Reptile [31]

Answer:

The frecuency is 1.2*10¹¹ Hz.

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).

The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f * λ.

In this case:

  • v= 300,000,000 m/s
  • f= ?
  • λ= 0.0025 m

Replacing:

300,000,000 m/s= f* 0.0025 m

Solving:

f= 300,000,000 m/s ÷0.0025 m

f= 1.2*10¹¹ \frac{1}{s} =  1.2*10¹¹ Hz

<u><em>The frecuency is 1.2*10¹¹ Hz.</em></u>

6 0
3 years ago
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