The work done in lifting a brick of mass 2kg through a height of 5m above the ground will be
1 answer:
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Answer:
-22.2 m/s²
Explanation:
The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:
(1)
For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:
(2)
Solving for time t:
(3)
The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:
(4)
Solving equation 4 for acceleration of rocket B:
(5)