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Phantasy [73]
3 years ago
8

The work done in lifting a brick of mass 2kg through a height of 5m above the ground will be

Physics
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

D. 100 J

Explanation:

Given

Mass (m) = 2 kg

Height (h) = 5 m

Acceleration due to gravity (g) = 10 m/s²

Now

Work done(W)

= m * g * h

= 2 * 10 * 5

= 100 Joule

Hope it will help :)❤

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Superman does an exhibition run at a track meet. When he runs the 200 m
Ber [7]

Answer:

6.32s

Explanation:

Given parameters:

Length of track and distance covered  = 200m

Acceleration  = 10m/s²

Unknown:

Time taken to cover the track  = ?

Solution:

To solve this problem, we apply one of the motion equations as shown below:

       S  = ut + \frac{1}{2} at²  

S is the distance covered

t is the time taken

a the acceleration

u is the initial velocity

The initial velocity of Superman is 0;

 So;

     S  =  \frac{1}{2} at²  

        200  =  \frac{1}{2} x 10 x t²  

          200  = 5t²  

            t²  = 40

            t  = 6.32s

5 0
3 years ago
The hottest climates on Earth are located near the Equator because this region
Ber [7]

You should select Choice-4 .

4 0
3 years ago
What could be used as another word for electrical potential
tekilochka [14]

Answer:

hey mate

answer is probably voltage as per me

as

Explanation:

Voltage, electric potential difference, electric pressure or electric tension is the difference in electric potential between two points, which is defined as the work needed per unit of charge to move a test charge between the two points

5 0
3 years ago
Read 2 more answers
10. In Freudian theory, which one of the following is an example of a Thanatos instinct, which includes aggression, trauma, and
Lelechka [254]
D substance abuse :) hope this helps
8 0
2 years ago
A skater with a mass of 72 kg is traveling east at 5.8 m/s when he collides with another skater of mass 45 kg heading 60° south
Akimi4 [234]

The final velocity is 5.87 m/s

<u>Explanation:</u>

Given-

mass, m_{1} = 72 kg

speed, v_{1} = 5.8 m/s

Mass_{2},m_{2}  = 45 kg

speed_{2},v_{2}  = 12 m/s

Θ = 60°

Final velocity, v = ?

Applying the conservation of momentum:

m_{1} X v_{1} + m_{2} X v_{2} = (m_{1} +m_{2} ) v

72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v

v = 417.6 + 540 X \frac{0.5}{117}

v = 417.6 + \frac{270}{117}

v = 5.87 m/s

The final velocity is 5.87 m/s

8 0
3 years ago
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