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sergejj [24]
3 years ago
9

A 3.0-kg block being pulled across a table by a horizontal

Physics
1 answer:
zlopas [31]3 years ago
6 0
Acceleration = 75/3 = 25 m/s^2
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A positively charged insulating rod is brought close to an object that is suspended by a string. If the object is repelled away
MrMuchimi

Answer: A positively charged insulating rod is brought close to an object that is suspended by a string. If the object is repelled away from the rod, we can conclude that the object is positively charged.

Explanation: To find the answer, we need to know more about the Electric charges and its properties.

<h3>What is meant by electric charge?</h3>
  • It can be defined as the basic fundamental property of matter causes to experience a force, when it is placed in an external electric field.
  • The charge of the particle can be positive, negative, and zero.
<h3>What are the fundamental properties of electric charge?</h3>
  • Additivity of charges
  • Conservation of charges
  • Quantization of charges.
  • Like charges repels and unlike charges attract.
  • It's a scalar quantity.

Thus, from the above, we can conclude that, when a positively charged insulating rod is brought close to an object that is suspended by a string. If the object is repelled away from the rod, we can conclude that the object is positively charged.

Learn more about the electric charge and its fundamental properties here: brainly.com/question/28020194

#SPJ4

3 0
2 years ago
A skier is moving down a snowy hill with an acceleration of 0.40 m/s2. The angle of the slope is 5.0∘ to the horizontal. What is
kirill115 [55]

Answer:

1.25377 m/s²

Explanation:

m = Mass of person

g = Acceleration due to gravity = 9.81 m/s²

\mu = Coefficient of friction

\theta = Slope

From Newton's second law

mgsin\theta-f=ma\\\Rightarrow mgsin\theta-\mu mgcos\theta=ma\\\Rightarrow \mu=\frac{gsin\theta-a}{gcos\theta}\\\Rightarrow \mu=\frac{9.81\times sin5-0.4}{9.81\times cos5}\\\Rightarrow \mu=0.04655

Applying \mu to the above equation and \theta=10^{\circ}

mgsin\theta-\mu mgcos\theta=ma\\\Rightarrow a=gsin\theta-\mu gcos\theta\\\Rightarrow a=9.81\times sin10-0.04655\times 9.81\times cos10\\\Rightarrow a=1.25377\ m/s^2

The acceleration of the same skier when she is moving down a hill is 1.25377 m/s²

3 0
3 years ago
A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or sh
zalisa [80]

Complete question:

Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a "crumple zone" in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 m as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. In contrast,  a passenger not wearing a seat belt or using an air bag decelerates over a distance of 5mm.

(a) A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys.

Answer:

The net force on the person as the air bad deploys is -6750 N backwards

Explanation:

Given;

mass of the passenger, m = 60 kg

velocity of the car at impact, u = 15 m/s

final velocity of the car after impact, v = 0

distance moved as the front of the car crumples, s = 1 m

First, calculate the acceleration of the car at impact;

v² = u² + 2as

0² = 15² + (2 x 1)a

0 = 225 + 2a

2a = -225

a = -225 / 2

a = -112.5 m/s²

The net force on the person;

F = ma

F = 60 (-112.5)

F = -6750 N backwards

Therefore, the net force on the person as the air bad deploys is -6750 N backwards

4 0
3 years ago
Which of the following is characteristic of the second stage within a demographic transition?
Elan Coil [88]
The answer is A) <span>The death rate begins to fall, but birth rates remain high for a time.</span>
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4 years ago
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What are the metric units of length?​
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Inches, feet, meters
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