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3 years ago

What are the things that severe thunderstorms have with them?

Chemistry

1 answer:

BARSIC [14]3 years ago

4 0

C) moisture, falling air, and a lifting mechanism

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Which statement describes a homogeneous catalyst?

Alik [6]

Answer:

it is in the same phase as the reactants

6 0

2 years ago

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10.0 g of gaseous ammonia and 6.50 g of oxygen gas are introduced into a previously evacuated 5.50 L vessel. If the ammonia and

Shalnov [3]

Answer:

The density is 3g/L

Explanation:

The reaction that occurs in the vessel is:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

10,0g of NH₃ are:

$10,0g * \frac{1mol}{17,031g} = 0,587 moles$

6,50 g of O₂ are:

$6,50g * \frac{1mol}{32g} = 0,203 moles$

For a complete reaction of O₂ there are necessaries:

$0,203 mol * \frac{4molNH_{3}}{5molO_{2}}= 0,163 moles of NH_{3}$

O₂ is limiting reactant. The excess moles of NH₃ are:

0,587 - 0,163 = 0,424 moles of NH₃

These moles are:

$0,424mol * \frac{17,031g}{1mol} =$ 7,22g of NH₃

Knowing O₂ is limiting reactant, mass of NO and H₂O are:

$0,203molO_{2}*\frac{4molNO}{5molO_{2}}*\frac{30,01g}{1molNO} =$ 4,87g of NO

$0,203molO_{2}*\frac{6molH_{2}O}{5molO_{2}}*\frac{18,02g}{1molH_{2}O} =$ 4,39g of H₂O

The total mass is: 7,22g + 4,87g + 4,39g = 16,48g ≡ 16,5g

-The same mass add in the first. By matter conservation law-

As vessel volume is 5,50L, density is:

16,5g/5,50L = 3g/L

I hope it helps!

7 0

4 years ago

Can a new element be discovered and be placed in between copper and nickel on the periodic table? Explain your answer.

laila [671]

Answer:

Yes and no

Explanation:

If a new element is discovered and needed to be put into the table of elements, there would have to be a process to find a spot for it. The table is used heavily in chemistry and it revolves around how the elements are placed. So there would have to be a developed spot for the new element.

3 0

3 years ago

You have 3.012x10^23 molecules of sodium chloride - how many grams do you have?

lapo4ka [179]

Answer:

29.26 gram

Explanation:

No of molecules = no of mole × Avogadro's number

No of molecules = mass in gram/ molar mass × Avogadros number

Mass in gram =No of molecules×molar mass / Avogadros number

Mass in gram = 3.012 ×10^23 × 58.5/6.02×10^23

29.26 gram

8 0

3 years ago

If you push a crate with 50N of force for 10 meters in 5 seconds how much power dis u use

morpeh [17]

Answer:

Hi... Your answer is 10*50=500

5 0

3 years ago

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