Heat capacity of aluminium = 0.900 J/g°C
While heat capacity of water = 4.186 J/g°C
Heat = heat gained by water + heat gained by aluminium
Heat gained by water = 100 × 4.186 × 30.5
= 12767.3 Joules
Heat gained by aluminium = 15 × 0.9 × 30.5
= 411.75 Joules
Heat required = 13179.05 Joules or 13.179 kJoules
A. solutions and colloids
Base + acid = salt + water
Example :
<span>HCl + NaOH = NaCl + H</span>₂<span>O
</span>
Answer A
hope this helps!
It can be predicted from the location on the periodic table.
P = 1.75 atm = __ kPa =
_mmHg
1 atm = 760 mm Hg
We can write the two conversion factors
1 atm / 760 mm Hg or 760 mm Hg / 1 atm
1.75 atm x ( 760 mm Hg \ 1 atm)
1330 mm Hg
1 atm = 101325 pa
We can write two conversion factors
1 atm / 101325 pa or 101325 pa / 1 atm
1.75 atm x ( 101325 pa / 1 atm )
177319 pa or 177.319 kPa
