Answer:
As it gets hydrolyzed easily.
Explanation:
The isocyanic acid may get polymerizes easily into cyanuric acid and a polymer cyamelide
Also, even at 0 °C temperature it may react with mositure and gets hydrolyzed into ammonia an carbon dioxide. Thus we generally prepare it in situ. Even after synthesis it is stroed at dry ice or liquid nitrogen at very low temperature.
The lewis structure is shown in the figure.
Answer:
5.01%
Explanation:
Density of vinegar = mass/volume
Mass of 10.00 mL = density x volume
= 1.006 x 10 = 10.06 g
From the equation of reaction:
1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.
mole of NaOH = molarity x volume
= 0.5062 x 0.01658
= 0.008392796 mole
0.008392796 mole of NaOH will therefore require 0.008392796 mole of CH3COOH.
mass of CH3COOH = mole x molar mass
= 0.008392796 x 60.052
= 0.504 g
Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%
= 5.01%
The percent by mass of acetic acid in the vinegar is 5.01%