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3 years ago

14

An important news announcement is transmitted by radio waves to people sitting next to their radios 42 km from the station and b

y sound waves to people sitting across the newsroom 9.26 m from the newscaster. Taking the speed of sound in air to be 343 m/s, who receives the news first?

1 answer:

Alik [6]3 years ago

8 0

Answer:

news will reach to the listener who are 42 km apart

Explanation:

given,

distance of the radios from the station = 42 Km

speed of the sound in the air = 343 m/s

distance of the people = 9.26 m

$time =\dfrac{distance}{speed}$

time taken by the signal to reach to the radio

speed of the electromagnetic wave to reach to the people

speed of electromagnetic wave = 3 × 10⁸ m/s

$t =\dfrac{42000}{3 \times 10^8}$

t = 1.4 μs

time taken to reach to the people

$time =\dfrac{distance}{speed}$

$t =\dfrac{9.26}{343}$

t = 27 ms

time taken by the station to radio is less.

hence, news will reach to the listener who are 42 km apart

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