It has to lose electrons to become positively charged, so it can attract a negatively charged oxygen ion.
Answer:
95.16 m
Explanation:
L = Range of radar = 7.8 km
= Wavelength = 2 cm
d = Diameter of antenna = 2 m
D = Distance
We have the relation
The smallest distance in meters that two speedboats can be from each other and still be resolved as two separate objects by the radar system is 95.16 m
This question is not complete.
The complete question is as follows:
One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?
Explanation:
a. Using the expression;
T = 2π√R/g
where R = radius of the space = diameter/2
R = 800/2 = 400m
g= acceleration due to gravity = 9.8m/s^2
1/T = number of revolutions per second
T = 2π√R/g
T = 2 x 3.14 x √400/9.8
T = 6.28 x 6.39 = 40.13
1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute
As we know that gravitational force on two planets will be given as
let
mass of star = M
mass of two planets are m1 and m2
their distance from star is r1 and r2
since the gravitational force of star is given on two planets to be same
so here we can say
now if the ratio of mass and distance is same then we can say that closer planet must have lesser mass to hold good for above equation
so correct answer will be
B) Yes, it is possible if the closer planet has less mass.