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2 years ago

How is Pluto currently classifed?

Physics

2 answers:

Zanzabum2 years ago

4 0

Answer:

Right now Pluto is classified as a <em>dwarf planet.</em>

Explanation:

melisa1 [442]2 years ago

4 0

Answer:

Dwarf planet

Explanation:

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A california condor is sitting on the top branch of a redwood tree and has a GPE of 12,100 J. If the condor has a mass of 8kg, w

DanielleElmas [232]

Answer:

william h. seward secured the purchase of alaska from:

Explanation:

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2 years ago

A pure sound wave, generated by a tuning fork, is considered a periodic wave. Which statement is true for this tuning fork sound

soldier1979 [14.2K]

Answer : Every wave has the same wave pattern.

Explanation : A pure sound wave has a single frequency and its generated by a tuning fork . The sound wave is a simple periodic wave.

When an object such as a guitar push and pull on the around it. When it pushes on the air, then the pressure increases and when it pull on the air, then the pressure decreases and sound waves are formed.

Hence, sound wave has the same wave pattern.

4 0

3 years ago

Read 2 more answers

what is the approximate weight of a 20-kg cannonball on the moon if the acceleration due to gravity is 1.6m/s^2

monitta

On Earth, a cannonball with a mass of 20 kg would weigh 196 Newtons.
With the formula F=mg, where F is the weight in Newtons, m is the mass, and g is the acceleration due to gravity on the Earth which is 9.8m/s^2.
F=20kg x 9.8m/s^2= 196 Newtons

BUT on the moon, acceleration due to gravity is 1.6 m/s^2,
so F=mg=20kgx1.6m/s^2= 32 N

5 0

3 years ago

A man and his dog are “walking” on flat Street. He is pulling on his stubborn dog with a force of 70 N Directed at a 30° angle f

Delvig [45]

Answer:

X component of force is 60.62 N.

Y component of force is 35 N.

Force of gravity on the dog is 245 N.

Magnitude of normal force is 210 N.

Explanation:

Given:

Force of pull is, $F=70\ N$

Mass of the dog is, $m=25\ kg$

Angle of inclination is, $\theta =30$ °

Acceleration due to gravity is, $g=9.8\ m/s^2$

The free body diagram of the dog is shown below.

The X and Y components of force of pull is given as:

$F_X=F\cos \theta=(70)\cos (30)=60.62\ N\\F_Y=F\sin \theta=(70)\sin(30)=35\ N$

Therefore, the X and Y components of the force are 60.62 N and 35 N respectively.

Force of gravity on the dog is the product of its mass and acceleration due to gravity. Thus,

$F_g=mg=25\times 9.8=245\ N$

Therefore, the force of gravity on the dog is 245 N.

Now, consider the motion in the vertical direction of the dog. As there is no motion in the vertical direction, the net force along the Y direction is 0. In other words, the total Upward force is equal to the total downward force.

From the free body diagram,

$N+F_Y=mg\\N=mg-F_Y\\N=245-35=210\ N$

Therefore, the normal force acting on the dog is 210 N.

6 0

3 years ago

half life worksheet answer key 3. What percent of a sample As-81 remains un-decayed after 43.2 seconds

Ivahew [28]

The final mass after decay can be obtained by using under given relation:

half life period of As-81 = 33 seconds

mf = mi x (1/2^n)

= 100 x ( 1/2^(43.2/33))

= 40.4 %

3 0

3 years ago