Answer:
The frequencies of sounds made by these two types of instruments are different because of the different ways that air will move at a closed or open end of the pipe. Open pipes do not produce superior tone than closed (or stopped) pipes, therefore different types of pipes are used to produce different tonal qualities.
Explanation:
You can write the equation in 3 different ways, depending on which quantity you want to be the dependent variable. Any one of the three forms can be derived from either of the other two with a simple algebra operation. They're all the same relationship, described by "Ohm's Law".
==> Current = (potential difference) / (resistance)
==> Potential difference = (current) x (resistance)
==> Resistance = (potential difference) / (resistance)
Lean your shoulders back and your waist forwards. Use your arms as a counter weight.
Answer:
option d) 12.0 V
Explanation:
Data provided in the question:
Potential difference due to a single charge (+Q), E = 3.0 V
Now,
The Electric potential for the system of charges is given as:
![E=\frac{1}{4\pi \epsilon_o}[\Sigma\frac{Q}{r}]](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D%5B%5CSigma%5Cfrac%7BQ%7D%7Br%7D%5D)
given for single charge, E = 3.0 V = ![\frac{1}{4\pi \epsilon_o}[\frac{Q}{r}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D%5B%5Cfrac%7BQ%7D%7Br%7D%5D)
.......(1)
so thus, for 4 charges, we have
![E=\frac{1}{4\pi \epsilon_o}[4\frac{Q}{r}]](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D%5B4%5Cfrac%7BQ%7D%7Br%7D%5D)
...............(2)
from 1 and 2 we have
E = 4 × 3.0 V = 12 V
Hence, option d) 12 V is the correct answer.
Answer:
The distance to the wall does not matter.
Explanation:
According to newton's third law, if you exert a force on the tennis ball to propel it northwards, it will exert equal and opposite force on you to propel you southwards. Therefore, how much you accelerate only depends on how fast you through the balls. And once a ball has left the system<em> ( consisting of you and the ball)</em>, it can no longer have an effect on you, so it doesn't matter whether the ball hits a wall nearby or the one millions of miles away.
<em>P.S: all of this is true assuming the balls don't bounce back from the wall and hit you in the face, which would surely give you additional southward acceleration, but it wouldn't be such a pleasant experience! </em>
