I’d say C: 1,3,4 because when you think about it section 2 and five would be balanced right?
Answer with explanation:
The Normalization Principle states that
Given
Thus solving the integral we get
The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below
Applying the limits and solving for A we get
![I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7Bk%7D%5B%5Cfrac%7B1%7D%7Be%5E%7Bkx%7D%7D-%5Cfrac%7Bx%7D%7Be%5E%7Bkx%7D%7D%5D_%7B0%7D%5E%7B%2B%5Cinfty%20%7D%5C%5C%5C%5CI%3D-%5Cfrac%7B1%7D%7Bk%7D%5C%5C%5C%5C%5Ctherefore%20A%3D-k)
Answer:
discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC source
Explanation:
Bulbs can emit light in several ways:
* When the emission is carried out by the heating of its filament, the bulb is called incandescent, in general its spectrum is similar to that of a black body, this is a continuous spectrum with a maximum dependent on the fourth power of the temperature of the filament.
* The emission can be by atomic transitions, in this case there is a discrete spectrum formed by the spectral lines of the material that forms the gas of the lamp, in general for the yellow emission the most used materials are mercury and sodium or a mixture of they.
Consequently, as discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC type
Answer: d. availability of places to play
Explanation: I think that it’s d because availability of space to do your physical activity is important. Availabilty of places to play is an environmental factor due to where you decide to play.
