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Katen [24]
4 years ago
7

Explain how to identify a starting position on a line

Physics
2 answers:
sergey [27]4 years ago
8 0

Answer:

When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.

Explanation:

Katyanochek1 [597]4 years ago
3 0

Answer:

We can easily find out the beginning point of the line by using dot representation.

Explanation: When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.

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This diagram shows a ball rolling from left to right along a frictionless
yanalaym [24]

I’d say C: 1,3,4 because when you think about it section 2 and five would be balanced right?

5 0
3 years ago
Given the initial wavefunction Ψ (x, 0) = Axexp (-k x) withx> 0 andk> 0, and Ψ (x, 0) = 0 forx <0, what value must A ta
madam [21]

Answer with explanation:

The Normalization Principle states that

\int_{-\infty }^{+\infty }f(x)dx=1

Given

f(x)=xe^{-kx}(x>0\\\\0(x

Thus solving the integral we get

\int_{0 }^{+\infty }A\cdot xe^{-kx}dx=1\\\\A\int_{0 }^{+\infty }\cdot xe^{-kx}dx=1

The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below

I=\int xe^{-kx}dx\\\\x\int e^{-kx}dx-\int \frac{d(x)}{dx}\int e^{-kx}dx\\\\-\frac{xe^{-kx}}{k}-\int 1\cdot \frac{-e^{-kx}}{k}\\\\\therefore I=\frac{e^{-kx}}{k}-\frac{xe^{-kx}}{k}

Applying the limits and solving for A we get

I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k

3 0
3 years ago
Which statement comparing examples of renewable and nonrenewable resources is true?
kiruha [24]
I believe the answer is A
6 0
4 years ago
Read 2 more answers
Viewed through a spectroscope, the spectral profile of a yellow street lamp has a narrow line in the yellow region of the visibl
muminat

Answer:

discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC source

Explanation:

Bulbs can emit light in several ways:

* When the emission is carried out by the heating of its filament, the bulb is called incandescent, in general its spectrum is similar to that of a black body, this is a continuous spectrum with a maximum dependent on the fourth power of the temperature of the filament.

* The emission can be by atomic transitions, in this case there is a discrete spectrum formed by the spectral lines of the material that forms the gas of the lamp, in general for the yellow emission the most used materials are mercury and sodium or a mixture of they.

Consequently, as discrete lines are observed by the spectroscope, the emission of the lamp is of the ATOMIC type

6 0
3 years ago
Help Please fast like now!!​
defon

Answer: d. availability of places to play

Explanation: I think that it’s d because availability of space to do your physical activity is important. Availabilty of places to play is an environmental factor due to where you decide to play.

7 0
3 years ago
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