The meters per second
+1t a second / 2t
        
             
        
        
        
Answer:
C1 + C2 = 30     parallel connection
C1 * C2 / (C1 + C2) = 7.2  series connection
C1 * C2 = 7.2 * (C1 + C2) = 216
C2 + 216 / C2 = 30    using first equation
C2^2 + 216 = 30 C2
C2^2 - 30 C2 + 216 = 0
C2 = 12 or 18    solving the quadratic 
Then C1 = 18 or 12
 
        
             
        
        
        
Answer:
The value of change in internal energy of the gas = + 1850 J
Explanation:
Work done on the gas (W) =  - 1850 J
Negative sign is due to work done on the system.
From the first law  we know that Q = Δ U + W ------------- (1)
Where Q = Heat transfer to the gas
Δ U = Change in internal energy of the gas
W = work done on the gas
Since it is adiabatic compression of the gas so heat transfer to the gas is zero.
⇒ Q = 0
So from equation (1)
⇒ Δ U = - W ----------------- (2)
⇒ W = - 1850 J (Given)
⇒ Δ U = - (- 1850)
⇒ Δ U = + 1850 J 
This is the value of change in internal energy of the gas.