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inna [77]
3 years ago
10

Texas has 4,015,000 beef cows in 2013. If one cow produced approx 209g of methane per day. How much methane was produced by the

beef cows in Texas in 2013
Physics
1 answer:
morpeh [17]3 years ago
7 0

Answer:

306,284,275,000

Explanation:

If 209g was made by 1 cow you would multiply 209 by 4,015,000 and if you are trying to find how much was made in a year get that number and multiply it by 365.

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The Sun appears to move relative to the stars. For example, right now the Sun is in front of the constellation Leo, but in a mon
Crank

Answer:

0.98°

Explanation:

The Sun appears to move across various constellation because of the Earth's revolution around it. This apparent motion is essentially same as the actual motion of the Earth. The orbit of Earth around the Sun is almost circular.

Time taken to complete one revolution = 365 days

Degrees traveled in 365 Days = 360°

The motion per day is

=\frac{360}{365}

= 0.98° per day

7 0
3 years ago
A mango fruit of mass 20g hangs on a tree 8m high. Calculate its potential energy.​
steposvetlana [31]

Answer:

1.568 J

Explanation:

PEg= mgΔh

      = 0.02×9.8×8

      = 1.568 J

8 0
3 years ago
A box is pulled with a horizontal force of 500N and moves 5m. What is the work done?
shepuryov [24]
The formula for work is N x m, which will equal in joules.
500 x 5 = 2,500 joules
8 0
4 years ago
Read 2 more answers
A force of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
dybincka [34]

Answer:

Explanation:

Given

Force=18lb

extension=8in

Using Hooke's law to get the spring constant(k)

F=ke

Then,

K=f/e

K=18/8

K=2.25lb/in

Work done by spring is given by

W=1/2Fe

Or W=1/2ke²

Then,

Work done in stretching the spring to 14in

W=1/2ke²

W=0.5×2.25×14²

W=220.5lbin

1 Inch-pounds Force to Joules = 0.113J

Then, to joules

W=0.133×220.5

W=29.33J

5 0
4 years ago
Steam at 0.6 MPa, 200 oC, enters an insulated nozzle with a velocity of 50 m/s. It leaves at a pressure of 0.15 MPa and a veloci
Rudiy27

Answer:

x2 = 0.99

Explanation:

from superheated water table

at pressure p1 = 0.6MPa and temperature 200 degree celcius

h1 = 2850.6 kJ/kg

From energy equation we have following relation

\dot m( h1+\frac{v1^2}{2}+ gz1 )+ Q = \dot m( h2+\frac{v2^2}{2}+ gz1) + W

\dot m( h1+\frac{v1^2}{2}) = \dot m( h2+\frac{v2^2}{2})

h1+\frac{v1^2}{2} = h2+\frac{v2^2}{2}

2850.6 + [\frac{50^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}] = h2 +[ \frac{600^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}]

h2 = 2671.85 kJ/kg

from superheated water table

at pressure p2 = 0.15MPa

specific enthalpy of fluid hf = 467.13 kJ/kg

enthalpy change hfg = 2226.0 kJ/kg

specific enthalpy of the saturated gas hg = 2693.1 kJ/kg

as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have

quality of steam x2

h2 = hf + x2(hfg)

2671.85 = 467.13 +x2*2226.0

x2 = 0.99

6 0
4 years ago
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