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Tpy6a [65]
3 years ago
9

You will have to zoom in to read it better

Physics
1 answer:
liraira [26]3 years ago
4 0

Changes speed

Passes through the boundary

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What is the acceleration of a 55 kg block of cement when pulled sideways with a net force of 356 N? Answer in units of m/s2.
puteri [66]
F=ma
a=F/m = 356/55 = .... m/s2
5 0
3 years ago
The number of molecules in a container is tripled and the kelvin temperature doubled. the volume remains unchanged. the new pres
Nonamiya [84]
N2 = 3*n1
T2 = 2*T1
V1 = V2

(n2 * T2)/P2 = (n1 * T1)/P1
3 n1 * 2 T1 / P2 = n1 *T1 / P1
P2 = 6*P1

Since P2 is 6P1, it is 6 times greater than original pressure
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3 years ago
When temperature and pressure are applied to sedimentary and igneous rock?
spin [16.1K]
Answer:

Igneous rock

Explanation:

Igneous rocks are formed through the cooling and solidification of magma. It undergoes changes in temperature and pressure that causes it to cool, solidify, and crystallize.
6 0
3 years ago
Acceleration usually has the symbol a. It is a vector. What is the correct way
Ghella [55]

Explanation:

a straight line under the letter

3 0
3 years ago
A student at another university repeats the experiment you did in lab. Her target ball is 0.860 m above the floor when it is in
dexar [7]

Answer:

K = 0.076 J

Explanation:

The height of the target, h = 0.860  m

The mass of the steel ball, m = 0.0120 kg

Distance moved, d = 1.50 m

We need to find the kinetic energy (in joules) of the target ball just after it is struck. Let t is the time taken by the ball to reach the ground.

h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}}

Put all the values,

t=\sqrt{\dfrac{2\times 0.860 }{9.8}} \\\\=0.418\ s

The velocity of the ball is :

v=\dfrac{1.5}{0.418}\\\\= $$3.58\ m/s

The kinetic energy of the ball is :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.0120\times 3.58^2\\\\=0.076\ J

So, the required kinetic energy is 0.076 J.

6 0
3 years ago
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