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nekit [7.7K]
4 years ago
9

Write an equation for the nth term of the arithmetic sequence: 64, 78, 92, 106, ...

Physics
1 answer:
Anna [14]4 years ago
4 0

If  64  is term #1 of the sequence,
then the general term is
                                      <em> T(n) = 50 + 14n </em>.


You might be interested in
A motorcyclist travels with an average speed of 6 m/s . If the cyclist is going to a friend's house 36 m away , how much time wi
vodka [1.7K]

Answer:

<h2>6 s</h2>

Explanation:

The time taken by the cyclist can be found by using the formula

t  = \frac{d}{v}  \\

v is the velocity

d is the distance

From the question we have

t =  \frac{36}{6}  \\  = 6

We have the final answer as

<h3>6 s</h3>

Hope this helps you

5 0
3 years ago
A spring with k = 500 N/m stores 704 J. How far is it extended from the equilibrium position
kaheart [24]

Given that:

k = 500 n/m,

work (W) = 704 J

spring extension (x) = ?

         we know that,

                      Work = (1/2) k x²

                          704 = (1/2) × 500 × x²

                            x = 1.67 m

A spring stretched for 1.67 m distance.

4 0
3 years ago
two boxes sit on a frictionless surface and are in contact with one another. the first box has a mass of 7 kg and the second box
egoroff_w [7]
The acceleration of the boxes depends on the mass and weight. 

we have a mass of 7 and 8 kilograms

if it took 25 N force to move box A, then you would take 25 and multiply by 8 then divide by 2. 

It will leave you with 100 N. 

finally take the sq rt of 100 to get 10
7 0
3 years ago
How far away is mars from the sun. why is is red?
Degger [83]
Mars is 139.58 million miles away from the sun. mars is red because its soil has iron oxide (rust particles) in it.
7 0
3 years ago
When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point
vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity \rightarrow 20m/s

\lambda = Wavelength \rightarrow 35*10^{-2}m

Therefore the frequency would be given as

f = \frac{20}{35*10^{-2}}

f = 57.14Hz

The frequency is directly proportional to the angular velocity therefore

\omega = 2\pi f

\omega = 2\pi *57.14

\omega = 359.03rad/s

Now the maximum speed from the simple harmonic movement is given by

V_{max} = A\omega

Where

A = Amplitude

Then replacing,

V_{max} = (1*10^{-2})(359.03)

V_{max} = 3.59m/s

Therefore the maximum speed of a point on the string is 3.59m/s

8 0
4 years ago
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