Answer:
(a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
Explanation:
Given that,
Weight of stone = 3.00 N
Height = 15 m
Speed = 25.0 m/s
(a). We need to calculate the speed at the moment of being thrown
Using work energy theorem


Put the value into the formula





(b). We need to calculate the maximum height
Using work energy theorem
![[tex]W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2](https://tex.z-dn.net/?f=%5Btex%5DW%3D%5Cdfrac%7B1%7D%7B2%7Dmv_%7B2%7D%5E2-%5Cdfrac%7B1%7D%7B2%7Dmv_%7B1%7D%5E2)

Here,
=0


Put the value into the formula


Hence, (a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
Answer:
a = 12 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
ΣF = m*a
where:
ΣF = sum of forces acting on a body [N] (units of Newtons)
m = mass = 0.5 [kg]
a = acceleration [m/s²]
Let's take the direction of positive forces to the right and negative forces directed to the left
2 + 8 - 4 = 0.5*a
6 = 0.5*a
a = 12 [m/s²]
Net force
As it's negative the box will move left
<span>Heat transfer between two substances is affected by specific heat and the "Temperature difference between them"
Hope this helps!</span>