Question

A bag contains 8 blue marbles 6 red marbles and 4 green marbles what is the probability of selecting a blue marble replaced it in the bag and then selecting a red marble

Answer 1

Answer:

$\dfrac{4}{27}$

Step-by-step explanation:

A bag contains 8 blue marbles 6 red marbles and 4 green marbles, 8 + 6 + 4 = 18 marbles in total.

The probability of selecting a blue marble is

$P(\text{blue marble})=\dfrac{\text{Number of blue marbles}}{\text{Total number of marbles}}=\dfrac{8}{18}=\dfrac{4}{9}$

Then the blue marble was replaced in the bag.

The probability of selecting a red marble is

$P(\text{red marble})=\dfrac{\text{Number of red marbles}}{\text{Total number of marbles}}=\dfrac{6}{18}=\dfrac{1}{3}$

The probability of selecting a blue marble replaced it in the bag and then selecting a red marble is

$P=\dfrac{4}{9}\cdot \dfrac{1}{3}=\dfrac{4}{27}$