All categories

3 years ago

How does a solution with a pH of 2 compare to a solution with a pH of 1

Chemistry

1 answer:

Cerrena [4.2K]3 years ago

7 0

Explanation:

A solution of pH 1 is more acidic than a solution of pH 2. Although both of them are strong acids that will ionize completely in aqueous solutions.

The pH scale is a scale that shows acidity or alkalinity of substance. It is graduated from 1 to 14.

Acids have a pH less than 7, bases have pH greater than 7 and neutral compounds have a pH of 7
The lower the pH less the 7, the more acidic they become.
Therefore, pH 1 is more acidic than a solution of pH 2.

Learn more:

pH brainly.com/question/12985875

#learnwithBrainly

You might be interested in

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but

alukav5142 [94]

Answer:

a) For nicotine, the protonated form is the present in stomach.

b) For caffeine, the neutral base form is the present in stomach.

c) For Strychinene, the protonated form is the present in stomach.

d) For quinine, the protonated form is the present in stomach.

Explanation:

In a basic dissociation for molecules with basic nitrogen, the equilibrium is:

A + H₂O ⇄ AH⁺ + OH⁻

<em>Where A is neutral base and AH⁺ is protonated form</em>

The basic dissociation constant, kb, is:

$K_{b} = \frac{[AH^+][OH^-]}{[A]}$

As pH in stomach is 2,5:

[OH] = $10^{-[14-pH]}$

[OH] = 3,16x10⁻¹² M

Thus:

$\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$ <em>(1)</em>

Using (1) it is possible to know if you have the neutral base or the protonated form, thus:

(a) nicotine Kb = 7x10^-7

$\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$\frac{7x10^{-7}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$221359 = \frac{[AH^+]}{[A]}$

[AH⁺}>>>>[A]

For nicotine, the protonated form is the present in stomach

(b) caffeine,Kb= 4x10^-14

$\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$\frac{4x10^{-14}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$0,0127 = \frac{[AH^+]}{[A]}$

[AH⁺}<<<<[A]

For caffeine, the neutral base form is the present in stomach

(c) strychnine Kb= 1x10^-6

$\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$\frac{1x10^{-6}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$314456 = \frac{[AH^+]}{[A]}$

[AH⁺}>>>>[A]

For Strychinene, the protonated form is the present in stomach

(d) quinine, Kb= 1.1x10^-6

$\frac{K_{b}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$\frac{1,1x10^{-6}}{3,16x10^{-12}} =\frac{[AH^+]}{[A]}$

$347851= \frac{[AH^+]}{[A]}$

[AH⁺}>>>>[A]

For quinine, the protonated form is the present in stomach.

I hope it helps!

7 0

3 years ago

At what temperature,in degrees°C, would 12.6g of HCN occupy 13.3L if the pressure is 0.97 atm

Flura [38]

Answer:

63.5°c

Explanation:

almost postive this is right

5 0

4 years ago

Read 2 more answers

What did Rutherford observe that surprised him?

Valentin [98]

Answer:

Some of the Alpha particles shot at the gold foil bounced back.

Explanation:

8 0

3 years ago

Read 2 more answers

A tetrahedral molecule has ___ regions of high electron density around the central atom. these molecules have central atoms with

shtirl [24]

<span>The answer is "A tetrahedral molecule has 4 regions of high electron density around the central atom. These molecules have central atoms with 0 lone pairs and 4 atoms bonded to them." Based on the octet rule, the atom must have 8 electrons to become stable. As a result, the molecule will not have lone pairs.</span>

3 0

4 years ago

Read 2 more answers

How many atoms of K are present in 195.49 grams of K? 3.0110 × 1024 6.0220 × 1024 1.1772 × 1026 4.5797 × 1027

Ierofanga [76]

<h2>Hello!</h2>

The answer is: $3.0110x10^{24}$