Answer:
(-10,0)(-5,0)(-10,-10)(-10,-5)
Step-by-step explanation:
If we count each box as one unit then we just count and if you left or down it is negative
Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer:
12.7
Step-by-step explanation:
you have to turn 4/5 into a decimal then subtract that from 13.50
Your answer is 10
<span>1. Length
</span><span>2. Height
</span><span>3. Depth
</span><span>4. Time
</span><span>5. Possible Worlds
</span><span>6. A Plane of All Possible Worlds With the Same Start Conditions
</span><span>7. A Plane of All Possible Worlds With Different Start Conditions
</span><span>8. A Plane of All Possible Worlds, Each With Different Start Conditions, Each Branching Out Infinitely
</span><span>9. All Possible Worlds, Starting With All Possible Start Conditions and Laws of Physics
</span><span>10. Infinite Possibilities</span>
<span>The tortoise crawls the whole 1000 m at 0.2 m/s, therefore, you must divide the distance by the rate of travel to find the time it took to complete the race. This gives us a time of 5,000 seconds to crawl the thousand meters. The hare runs the first 200 meters at 2 m/s, meaning that takes 100 seconds. The last 800 meters divided by the speed of 3 m/s gives us a time of 266 seconds. These two numbers must be added to the hare's rest time, converted from 1.3 hours into seconds by multiplying that number by 60 (for minutes in an hour) then 60 again (for seconds in a minute). 1.3 hours is equal to 4680 seconds. Therefore, the whole race took the hare 5,046 seconds, making it slightly slower than the hare, who finished in 5,000 seconds flat.</span>