The amount of energy lost at the transition between each trophic level of the pyramid of energy is about 90%.
There are a total of 4 trophic levels.
The producers which bare plants represent the first trophic level. Herbivores represent the second trophic level. Carnivores represent the third trophic level. Top carnivores represent the fourth trophic level.
The 10 % rule is followed by the energy flow in a food chain. It means that moving from one trophic level to another, only 10% of energy is transferred and the rest is lost in the atmosphere.
So the 90% percent energy is lost at the transition between each trophic level of the pyramid of energy.
If you need to learn more about the trophic levels, click here
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Answer:
57.885.8 kg weight of the container
Explanation:
The volume of the balloon * density of water = buoyant force of balloon
volume of a sphere = 4/3 pi r^3
= 4/3 pi * (1.5)^3 = 14.14 m^3 <===balloon volume
Now, find the buoyant force on the container ALONE ....
5.8 * 2.6 * 2.8 * 1027 = 43 364 kg <===== buoyant force
Now add the buoyant force of the balloon to find the weight
43 364 + 14.14 * 1027 = 57885.8 kg
Answer:
ω2 = 216.47 rad/s
Explanation:
given data
radius r1 = 460 mm
radius r2 = 46 mm
ω = 32k rad/s
solution
we know here that power generated by roller that is
power = T. ω ..............1
power = F × r × ω
and this force of roller on cylinder is equal and opposite force apply by roller
so power transfer equal in every cylinder so
( F × r1 × ω1) ÷ 2 = ( F × r2 × ω2 ) ÷ 2 ................2
so
ω2 =
ω2 = 216.47
Well if the ship was in space their shouldn’t be a loud bang. Because you can’t hear anything in space
Answer:
Hello your question is incomplete below is the complete question
Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000
answer : V = 1.624* 10^-5 m/s
Explanation:
First we have to calculate the value of a
a = 93 * 10^6 mile/m * 1609.344 m
= 149.668 * 10^8 m
next we will express the distance between the earth and the sun
--------- (1)
a = 149.668 * 10^8
E (eccentricity ) = ( 1/60 )^2
= 90°
input the given values into equation 1 above
r = 149.626 * 10^9 m
next calculate the Earths velocity of approach towards the sun using this equation
------ (2)
Note :
Rc = 149.626 * 10^9 m
equation 2 becomes
(![V^2 = (\frac{4\pi^{2} }{149.626*10^9})](https://tex.z-dn.net/?f=V%5E2%20%3D%20%28%5Cfrac%7B4%5Cpi%5E%7B2%7D%20%20%7D%7B149.626%2A10%5E9%7D%29)
therefore : V = 1.624* 10^-5 m/s