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Vsevolod [243]
3 years ago
10

A piece of aluminum (bulk modulus 7.1 x 1010 N/m2) is placed in a vacuum chamber where the air pressure is 0.781 x 105 Pa. The v

acuum pump is then turned on and the pressure is further reduced to zero. Determine the fractional change V/V0 in the volume of the aluminum
Physics
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

{\dfrac{\Delta V}{V}}=11\times 10^{-7}

Explanation:

Given that

Bulk modulus ,K = 7.1 x 10¹⁰  Pa

The pressure P₁ = 0.781 x 10⁵ Pa

The final pressure P ₂ = 0 Pa

We know that bulk modulus given as

K=\dfrac{\Delta P}{\dfrac{\Delta V}{V}}

Now by putting the values

K=\dfrac{\Delta P}{\dfrac{\Delta V}{V}}

7.1\times 10^{10}=\dfrac{0.781\times 10^5}{\dfrac{\Delta V}{V}}

{\dfrac{\Delta V}{V}}=\dfrac{0.781\times 10^5}{7.1\times 10^{10}}

{\dfrac{\Delta V}{V}}=11\times 10^{-7}

Therefore fractional change will be 11 x 10⁻⁷.

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