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sladkih [1.3K]
3 years ago
13

In the graph below, the acceleration of an object is plotted against the net force applied to the object. When a net force of 2

newtons is applied,
A. 1 m/s^2
B. 2 m/s^2
C. 3 m/s^2
D. 4 m/s^2

Chemistry
1 answer:
Westkost [7]3 years ago
3 0

Answer:

The answer to your question is: letter A.

Explanation:

In this conditions we observe that the acceleration is 1 m/s².

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Which property of a substance is not altered by a physical change?
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3 years ago
Is work done whenever you hold a heavy object for a long time?
AnnZ [28]

No, work is not done whenever you hold a heavy object for a long time

<h3>What is work done ?</h3>

The result of a force's displacement and its component of force exerted by the object in the direction of displacement is what is known as the force's work. When we push a block with some force, the body moves quickly and work is completed.

  • No work, as that term is used here, is done until the object is moved in some way and a component of the force travels along the path that the object is moved. Because there is no displacement when holding a heavy object still, energy is not transferred to it.

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7 0
1 year ago
Radioactive decay can be described by the following equation where is the original amount of the substance, is the amount of the
soldi70 [24.7K]

Answer:

Iron remains = 17.49 mg

Explanation:

Half life of iron -55 = 2.737 years (Source)

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{2.737}\ year^{-1}

The rate constant, k = 0.2533 year⁻¹

Time = 2.41 years

[A_0] = 32.2 mg

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,  

[A_t]=32.2\times e^{-0.2533\times 2.41}\ mg

[A_t]=32.2\times e^{-0.610453}\ mg

[A_t]=17.49\ mg

<u>Iron remains = 17.49 mg</u>

8 0
3 years ago
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