Answer:
Number of neutrons and stability
Explanation:
An isotope of an element is basically the same element but with different number of neutrons. For example here, boron can exist in the forms of boron-10 and boron-11, and so the latter would have one more neutron than the former one.
Adding an extra neutron may or may not disrupt the strong force that much, and so the half-life and stability of the new isotope can be slightly different than its most stable one.
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Answer:
Q = 4019.4 J
Explanation:
Given data:
Mass of ice = 20.0 g
Initial temperature = -10°C
Final temperature = 89.0°C
Amount of heat required = ?
Solution:
specific heat capacity of ice is 2.03 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 89.0°C - (-10°C)
ΔT = 99°C
Q = 20.0 g ×2.03 J/g.°C × 99°C
Q = 4019.4 J
Answer: 40.68 kPa
Explanation:
Given that,
Original volume of gas V1 = 21.7 mL
Original pressure of gas P1 = 98.8 kPa
New volume of gas V2 = 52.7 mL
New pressure of gas P2 = ?
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
98.8 kPa x 21.7 mL = P2 x 52.7L
2143.96 kPa L = 52.7 L x P2
P2 = 2143.96 kPa L / 52.7 L
P2 = 40.68 kPa
Thus, the new pressure of the gas is 40.68 kPa.
