3 years ago

Work and power!

Physics

1 answer:

Tema [17]3 years ago

5 0

Answer:

The work done in a unit of time is C. Power.

Explanation:

Hope this helps

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Answer:

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Explanation:

Given

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b) We can use I or II, then

x = 52 + 21.5*(4.16)

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Read 2 more answers

Find the length of a pendulum that oscillates with a frequency of 0.16 hz. the acceleration due to gravity is 9.81 m/s 2 . answe

Vsevolod [243]

The period of the pendulum is the reciprocal of the frequency:
$T= \frac{1}{f}= \frac{1}{0.16 Hz}=6.25 s$

The period of the pendulum is given by
$T=2 \pi \frac{L}{g}$
where L is the length of the pendulum, and g the acceleration of gravity. By re-arranging the formula and using the value of T we found before, we can calculate the length of the pendulum L:
$L=g \frac{T^2}{(2 \pi)^2}=(9.81 m/s^2) \frac{(6.25 s)^2}{(2 \pi)^2}=9.71 m$

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2 years ago