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3 years ago

which of these equations are balance a) 3 H2SO + 2AI = AI2(SO4)3 3H2 b) 2KCI + Pb(NO3)2 = 2KNO3 + PbCI2

Chemistry

1 answer:

mihalych1998 [28]3 years ago

6 0

Both equations are balanced.

a) 3H₂SO₄ + 2Al ⟶ Al₂(SO₄)₃ + 3H₂

On the left On the right

6H 6H

3S 3S

12O 12O

2Al 2Al

b) 2KCl + Pb(NO₃)₂ ⟶ 2KNO₃ + PbCl₂

On the left On the right

2K 2K

2Cl 2Cl

1Pb 1Pb

2N 2N

6O 6O

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I need you to solve for me plzzzzzz

Sergeu [11.5K]

Answer:

.0556 L

Explanation:

First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.

Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).

Finally, the answer will be .0556 L.

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3 0

2 years ago

34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases

Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

Where q is heat of reaction in J,

m is the mass of the solution in g,

S is specific heat of the solution = 4.184J/g°C

ΔT is change in temperature = 11.21°C

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0

3 years ago

Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

6 0

3 years ago

What the three injuries which can happen in the lab when chemicals are used incorrectly?

stepladder [879]

Answer:

Eye injuries,Burns,Respiratory injuries

7 0

3 years ago

When 0.313 g of Mg is heated strongly in a nitrogen (N2) atmosphere, a chemical reaction occurs. The product of the reaction wei

borishaifa [10]

Answer:

Mg₃N₂ (magnesium nitride)

Explanation:

M(total) = M(mg) + M (n)

M (n) = M(total) - M(mg)

= 0.433g - 0.313g

= 0.12g

mole (N) = 0.12g / 14.0067 g/mol

= 0.008567

mole Mg = 0.313g / 24.3050 g/mol

= 0.012878

Mg = 0.012878 / 0.008567

= 1.5

N = 0.008567 / 0.008567

= 1

multiply by 2 to get whole numbers

Mg = 1.5 × 2 = 3

N = 1 × 2 = 2

Mg₃N₂ (magnesium nitride)

8 0

3 years ago