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BARSIC [14]
3 years ago
8

Technician A says voltage will not exist between any two points in a circuit if the potential is zero. Technician B says corrosi

on is NOT a contributing factor to voltage drop. Who is correct?
Physics
1 answer:
nordsb [41]3 years ago
5 0

Answer:

  • <u>Option-(A):</u> If there is no potential or we can say the difference in total amount of charges present inside the system then the voltage's value wont be greater then "0" inside the circuit or system.

Explanation:

  • While, the circuit or system requires the difference in total amount of energy that each atom on that spot has, as this potential energy difference or the total number of charges difference contribute to having a more specified manner of voltage,v in that system. And thus the flow of charges,Q from a point of origination or source towards a region of lower energy is all due to this difference in potential.
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It is Real,Virtual,The Same Size, Inverted
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2 years ago
explain why a high-speed collision between two cars would cause more damage than a low-speed collision between the same two cars
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The force equation can easily prove this.  F=ma.  This states that the force on an object is equal to mass times acceleration.  If the mass stays the same and the velocity of the cars increases than that means there is a larger force.  This is because in both cases the cars are stopping in almost an instant and the times of the crashes are theoretically identical.  Acceleration is the change in velocity over time.  If the velocity is higher with the same amount of time than that means there is a higher acceleration.  If you plug a higher acceleration into the force equation then you wind up with a higher force and in turn a more damaging collision.
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3 years ago
MA of the first class lever may be equal to, greater than 1.Why​
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3 years ago
Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu
ladessa [460]

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving  toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm (\lambda_{0} = 434nm, \lambda_{0} = 410nm)

Redshift: \lambda_{measured}  >  \lambda_{0}

Blueshift: \lambda_{measured}  <  \lambda_{0}

Since, \lambda_{measured} (444nm) is greater than \lambda_{0} (434 nm) and \lambda_{measured} (420nm) is greater than \lambda_{0} (410 nm), it can be concluded that the star is moving away from the observer

6 0
3 years ago
Using Figure 2, what is the momentum of Train Car A before the collision?
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Answer:

Option A. 180000 Kgm/s.

Explanation:

From the question given above, the following data were obtained:

For Train Car A:

Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

For Train Car B:

Mass of train car B = 45000 Kg

Velocity of train car B = 0 m/s

Momentum is simply defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

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Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

Momentum = mass × velocity

Momentum = 45000 × 4

Momentum of train car A = 180000 Kgm/s

5 0
2 years ago
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