Answer:
first law: an object remains in uniform motion except an external force has acted upon it eg a ball in stable motion doesn't move until one moves or kicks it
second law:the body acted upon by an external force gains a momentum which is directly proportional to the applied force and acts in the direction of the force
third law: to every action there is an equal and opposite reaction eg if u push someone the person moves backward away from you and not towards you
Answer:
Explanation:
The total fluid mass can be obtained by multiplying the mass flow rate by the time flow rate.
Mass flow rate is given as
m = ρAv
Where
m is mass flow rate
ρ is density
A is area and it is given as πr²
v is velocity
Then,
M = mt
Where M is mass and t is time
Them,
M = ρAv × t
M = ρ× πr² × v × t
Given that, .
Radius of pipe is
r = 0.089m
velocity of pipe is
v = 3.3m/s
Time taken is
t = 1 hour = 3600 seconds
Density of water is
ρ = 1000kg/m³
M = ρ× πr² × v × t
M = 1000 × π × 0.089² × 3.3 × 3600
M = 295,628.52 kg
M = 2.96 × 10^5 kg
<span>To do this question, we need to know that momentum is conserved, meaning the overall velocity of the two balls has to be the same before and after the collision. </span>
<span>After collision... </span>
<span>Ball 1: 4.33m/s *cos 30 = 3.75 m/s (x-component) </span>
<span>4.33m/s * sin 30 = 2.165 m/s ( y-component) </span>
<span>Ball 2 (struck ball): 5 m/s - 3.75m/s = 1.25 m/s (x-component) </span>
<span>-2.165 m/s (y-component) note: it has to be in the opposite direction to conserve momentum </span>
<span>tan-1(2.165/1.25) = 60 degrees </span>
<span>Struck ball's velocity = sqrt(1.25^2 + 2.165^2) = 2.5 m/s at 60 degree with respect to the original line of motion. </span>
<span>Hope you understand!</span>
Answer:
1,700feet
Explanation:
If an object in free fall travels a distance s that is directly proportional to the square of the time t, this can be represented mathematically as;
S = kt²where;
k is the proportionality constant
K = s/t²
s1/t1²= s2/t2²= Sn/tn²= k for values of the distance and time. Using the formula
s1/t1² = s2/t2² where;
s1 is the falling distance in time t1 s2 is the falling distance in time t2
Given s1 = 1088feet, t1 = 8secs, s2 = ? t2 = 10secs
Substituting this value in the formula to get s2, we have;
1088/8²= s2/10²
64s2= 108800
s2 = 108800/64
s2 = 1,700feet
This means the object will fall a distance of 1,700feet in 10seconds
Answer:
12.5 ft/s
Explanation:
Height of person = 6 ft
height of lamp post = 10 ft
According to the question,
dx / dt = 5 ft/s
Let the rate of tip of the shadow moves away is dy/dt.
According to the diagram
10 / y = 6 / (y - x)
10 y - 10 x = 6 y
y = 2.5 x
Differentiate both sides with respect to t.
dy / dt = 2.5 dx / dt
dy / dt = 2.5 (5) = 12.5 ft /s
