Answer:
Q₁ > Qo
C₁ > Co
Explanation:
We know that

Lets take relative permitivity of green plate =k
So new capacitance value

From above two expression we can say that
C₁ = kCo
k > 1
So we can say that
C₁ > Co
We also know that
Co = Qo V
C₁ = Q₁ V
From above we can say that
Co/C₁ = Qo/Q₁ ( C₁ > Co ⇒Co/C₁ <1)
Co/C₁ <1
So we can say that
Qo/Q₁ < 1
Q₁ > Qo
Then they will most likely slow down unless they do high knees or something like that
Scientists could investigate this idea by making cathode ray tubes out of different materials to see if the ray was the same.
The answer would be to research the need. This should have been done before the project began.
Answer:
<em>The difference in pressure between the external air pressure, and the internal air pressure of the middle ear.</em>
Explanation:
First of all, we should note that pressure decreases with height and increases with depth. The air within the middle ear (between the ear drum and the Eustachian tube) adjusts itself to respond to the atmospheric pressure, or when we yawn. At a high altitude like on the hill, the air pressure in the middle ear, is fairly low (this is to balance the low air pressure at this height). While riding down the hill quickly, there is little time for the air pressure in the ear to readjust itself to the increasing external air pressure, causing the external air to push into the ear drum. Along the way, the air within the middle ear is adjusted by the opening of the Eustachian tube, allowing more air into the space in the middle ear to balance the external air pressure. This readjustment causes the ear to pop.