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Anastasy [175]
3 years ago
12

What weather does a occluded front bring?

Physics
1 answer:
8090 [49]3 years ago
6 0
Hey I hope this helps in any way.

As the front<span> moves through, cool, fair </span>weather<span> is likely to follow. Warm </span>front<span> Forms when a moist, warm air mass slides up and over a cold air mass. As the warm air mass rises, it condenses into a broad area of clouds. A warm </span>front<span> brings gentle rain or light snow, followed by warmer, milder </span>weather<span>.</span>
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Which of the following represents a system that is completely open?
fredd [130]
<span>The correct answer is D. The system that is completely open of the available answers would be an open pot of boiling water. This is due to the fact that an open system is defined as one in which energy or mass can be put out into or taken from the environment. Therefore, the evaporation of water due to the heat when a pot is boiling would be an example of lost energy, and therefore this is an open system.</span>
5 0
3 years ago
Read 2 more answers
John often sees squiggly lines when he looks at a bright sky or white paper. His doctor says that they are called eye floaters,
trapecia [35]

Answer- It's B, i double checked it on a few websites

8 0
2 years ago
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A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have a
Verizon [17]

Answer:

The shear deformation is \Delta x=3.34\times10^{-6}\ m.

Explanation:

Given that,

Shearing force F = 600 N

Shear modulus S = 1\times10^{9}\ N/m^2

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

S=\dfrac{Fl_{0}}{A\Delta x}

\Delta x=\dfrac{Fl_{0}}{(\dfrac{\pi d^2}{4})S}

\Delta x=\dfrac{4Fl_{0}}{\pi d^2 S}

Put the value into the formula

\Delta x=\dfrac{4\times600\times0.700\times10^{-2}}{3.14\times1\times10^{9}\times(4.00\times10^{-2})^2}

\Delta x=3.34\times10^{-6}\ m

Hence, The shear deformation is \Delta x=3.34\times10^{-6}\ m.

7 0
3 years ago
A particle that has mass m and charge q enters a uniform magnetic field that has magnitude B and is directed along the x axis. T
Usimov [2.4K]

Answer:

a) The trajectory will be a helical path.

b) θ = 2*π rad

Explanation:

a) Since the initial velocity of the particle has a component parallel (x-component) to the magnetic  field B , the trajectory will be a helical path.

b) Given

t = 2*π*m/(q*B)

We can use the equation

θ = ω*Δt

where

θ is the angular displacement

ω is the angular speed, which is obtained as follows:

ω = q*B/m

then we have

θ = (q*B/m)*2*π*m/(q*B)

⇒  θ = 2*π rad

6 0
3 years ago
A boy pushes a 50 kilogram wagon with a force of 4 N east while an orangutan pushes the wagon
ladessa [460]
The wagon does not move
6 0
3 years ago
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