E is always less than or equal to Eo, so the dielectric constant is greater than or equal to 1. The larger the dielectric constant, the more charge can be stored, therefore its greater most of the time
Answer:
- 58 cm
Explanation:
refractive index, n = 1.6
radius of curvature of left face, R1 = - 65 cm
Radius of curvature of the right face, R2 = 75 cm
Use the lens maker's formula
f = - 58 cm
Thus, the focal length of the lens is - 58 cm.
Hi, thank you for posting your question here at Brainly.
First, you have to draw the system for better understanding. Pls refer to the attached image.
Since the system is not moving, the summation of forces are zero since they are at equilibrium
Let's base on the 2-kg object first to find the tension (T) of the rope.
Forces in the y-direction = 0 = T - W
0 = T - 2 kg (9.81 m/s2)
T = 19.62 N
Let's base on the 2.41 kg load.
Forces in the y-direction = 0 = Fn - Wy
0 = Fn - (2.41kg)(9.81m/s^2)(cos47)
Fn = 16.12 N
Forces in the x-direction = 0 = Ff + T - Wx
0 = Ff + 19.62 - (2.41kg)(9.81m/s^2)(sin47)
Ff = -2.33 N
The magnitude of the frictional force is 2.33 N.
Answer:
a) k = 120 N / m
n b) f = 0.84 Hz
, c) v = 1,056 m / s
, d) x=0
Explanation:
a) To find the spring constant let's use Hooke's law
F = - k x
k = -F / x
k = - 24.0 / (0.2)
k = 120 N / m
b) the angular velocity in harmonic motion is
w = √ k / m
w = √ 120 / 4.30
w = 5.28 rad / s
The angular velocity is related to the frequency
w = 2π f
f = w / 2π
f = 5.28 / 2π
f = 0.84 Hz
c) System speed is
v = dx / dt = -A w sin (wt +φ)
The speed is maximum when sin (wt + φ) = ±1
v = A w
v = 0.200 5.28
v = 1,056 m / s
d) in which position the velocity is maximum, as the velocity is a function of the sine and the position of the cosine when the sine is maximum the cosine is zero, so
x = A cos 0 = 0
x=0
The light bends around the edges of the slit B I think