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Vesna [10]
3 years ago
12

When a car maintains a velocity of exactly 65 mph, what is it's acceleration​

Physics
2 answers:
Illusion [34]3 years ago
8 0

Answer:

0 ms^-2

Explanation:

Acceleration is the change in velocity. If something is going at a constant velocity, the velocity is not changing. So, there is no acceleration.

Readme [11.4K]3 years ago
4 0

When a car maintains a velocity of exactly 65 mph, it's acceleration​ is zero.

<h3>What is acceleration?</h3>

The acceleration is time rate of change of velocity.

When the velocity is not changing with respect to time, it is said to be an object moving with constant velocity.

At constant velocity, there is no acceleration.

Thus, when a car maintains a velocity of exactly 65 mph, it's acceleration​ is zero.

Learn more about acceleration.

brainly.com/question/12550364

#SPJ2

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A boat sails south with the help of a wind blowing in the direction S36°E with magnitude 300 lb. Find the work done by the wind
goldfiish [28.3K]

Answer:

The work done by the wind as the boat moves 130 ft is (rounded) W= 31,550 ft-lb.

Explanation:

F= 300 lb < -54º

Fsouth= 300 lb * cos(36º)

Fsouth= 242.7 lb

d= 130 ft

W= F*d

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3 years ago
A 5.00 kilogram block slides along a horizontal,frictionless surface at 10.0 meters per second. for 4.00 seconds. The magnitude
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In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
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Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
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A dime is placed in front of a concave mirror that has a radius of curvature R = 0.40 m. The image of the dime is inverted and t
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Answer:

distance between the dime and the mirror, u = 0.30 m

Given:

Radius of curvature, r = 0.40 m

magnification, m = - 2 (since,inverted image)

Solution:

Focal length is half the radius of curvature, f = \frac{r}{2}

f = \frac{0.40}{2} = 0.20 m

Now,

m = - \frac{v}{u}

- 2 = -\frac{v}{u}

\frac{v}{u} = 2                  (2)

Now, by lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{v} = \frac{1}{f} - \frac{1}{u}

v = \frac{uf}{u - f}            (3)

From eqn (2):

v = 2u

put v = 2u in eqn (3):

2u = \frac{uf}{u - f}

2 = \frac{f}{u - f}

2(u - 0.20) = 0.20

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A scientist heats up a container full of neon gas. What will most likely happen to the container as the gas heats up?
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