It is highly reactive and when it is kept in open it does react with the oxygen present in the surroundings and burns therefore it is kept immersed in kerosene and please thank me and if you need more comment
P = 1.5atm ≈ 1519.88hPa
V = 8.56L
R = 83.1 [hPa*L] / [mol*K]
T = 0°C =273K
pV = nRT |:RT
n = pV / RT
n = [1519.88hPa*8.56L] / [83.1 [hPa*L] / <span>[mol*K] * 273K]
n </span>≈ <u>0.57mol</u><span><u> </u></span>
Answer : The concentration of solution in ppm is, 500 ppm
Solution : Given,
Mass of solute (glucose) = 0.125 g
Mas of solution = 250 g
Parts per million (ppm) : It is defined as the mass of a solute present in one million
parts by the mass of the solution.
Formula used :

Now put all the given values in this formula, we get

Hence, the concentration of solution in ppm is, 500 ppm
Answer:
The concentration is 50.6 g/L
Explanation:
pa BRAINLYES PO TY