Answer: 0.01 m
Explanation: The formulae for capillarity rise or fall is given below as
h = (2T×cosθ)/rpg
Where θ = angle mercury made with glass = 50°
T = surface tension = 0.51 N/m
g = acceleration due gravity = 9.8 m/s²
r = radius of tube = 0.5mm = 0.0005m
p = density of mercury.
h = height of rise or fall
From the question, specific gravity of density = 13.3
Where specific gravity = density of mercury/ density of water, where density of water = 1000 kg/m³
Hence density of mercury = 13.3×1000 = 13,300 kg/m³.
By substituting parameters, we have that
h = 2×0.51×cos 50/0.0005×9.8×13,300
h = 0.6556/65.17
h = 0.01 m
Answer: 3.33 m/s
Explanation:
Assuming the questions is to convert 12 km/h to meter per second (m/s), let's begin:
In order to make the conversion, we have to know the following:
And:
Keeping this in mind, we can make the conversion:
Then:
-6.98 × 10-^7 is the answer <3
Answer:
a)48300 times
b)P = 821100 kg · m/s
Explanation:
Given that
m = 48300 kg
v= 23 m/s
We know that linear momentum (P) given as
P = m v
P = 48300 x 23 kg · m/s
So we can say that truck momentum is 48300 times its velocity.
Now given that
v= 17 m/s
P = m v
P = 48300 x 17 kg · m/s
P = 821100 kg · m/s
E = 0.25 = m*g*h
<span>h = 0.25/(m*g) = 0.25/(0.125*10) = 0.25/1.25 = 1/5 = 0.20 m
I hope this helps you have a great day and im sorry it took so long to get an answer</span>
