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serious [3.7K]
3 years ago
15

Drag each label to the correct location.

Physics
1 answer:
photoshop1234 [79]3 years ago
7 0

first two continental while second rest

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Short, difficult activities that push your body are called
Reika [66]

Answer: A

Explanation: Any short-duration exercise that is powered primarily by metabolic pathways that do not use oxygen. Examples

of anaerobic exercise include sprinting and weight lifting.

4 0
2 years ago
Read 2 more answers
A point charge that is exactly q =3 mu or micro CC is at the origin. In this problem, assume that the Coulomb constant k = 8.99
Simora [160]

Answer:

(a) V1 = 8990.00 V

V2 = 8960.13 V

Explanation:

Parameters given:

q =3 mC

k = 8.99 * 10⁹ Nm²/C²

x1 = 3 m

x2 = 3.01 m

Electric potential is given as:

V = kq/r

Where

k = Coulombs constant

q = charge

r = distance

Potential at x1 is:

V1 = (8.99 * 10⁹ * 0.000003)/(3)

V1 = 8990.00V

Potential at x2 is:

V2 = (8.99 * 10⁹ * 0.003)/(3.01)

V2 = 8960.13 V

7 0
3 years ago
Read 2 more answers
Blue light has a typical frequency of 6.67 x 10 14 1014 Hz. What is the wavelength associated with this frequency?
DerKrebs [107]
First recall the equation that relates frequency to wavelength:

v = fw

Note that the v is the speed of light, a constant. Now plug in the information we know!

(3×10^8) = (6.67 × 10^14) w

Hit the numbers on the calculator and you'll get the wavelength, w. If you comment your answer I'll check it for you. :)

5 0
4 years ago
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What is the thinnest film (but not zero) of MgF2 (n = 1.38) on glass that produces a strong reflection for orange light with a w
Art [367]

The concept required to solve this problem is related to thin film interference.

The path length difference between two waves one is reflected from top surface of the film and the bottom surface of the film is equal to twice the thickness of the film:

\gamma = 2t

Where,

\gamma = Path length difference

t = thickness

At the same time we have that the constructive interference condition for a thin film interference for strongly reflected rays is

\gamma = m\lambda

Where

\gamma = Path length difference

\lambda = wavelength

m = Any integer (order of the equation) which represent the number of repetition of the spectrum

Equation both expression we have

2t = m\lambda

Re-arrange to find the thickness we have

t = m\frac{\lambda}{2n}

Our values are given as

m = 1

\lambda= 597nm

n = 1.38

Replacing,

t = (1)\frac{597}{2(1.38)}

t = 216.3nm

Therefore the thinnest thickness of the film is 216.3nm

6 0
3 years ago
Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an
galben [10]

Answer:

\triangle P=1.95*10^{-4}

Explanation:

Mass m=0.001

Diameter d=1.2m

Length l=10m

Generally the equation for Volume flow rate is mathematically given by

 Q=AV

 V=\frac{Q}{\pi/4D^2}

 V=\frac{0.001}{\pi/4(1.2)^2}

 V=8.84*10^{-4}

Generally the equation for Friction factor is mathematically given by

 F=\frac{64}{Re}

Where Re

Re=Reynolds Number

 Re=\frac{pVD}{\mu}

 Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}

 Re=1040

Therefore

 F=\frac{64}{Re}

 F=\frac{64}{1040}

 F=0.06

Generally the equation for Friction factor is mathematically given by

 Head loss=\frac{fLv^2}{2dg}

 H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}

 H=19.9*10^{-9}

Where

H=\frac{\triangle P}{\rho g}

\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}

\triangle P=H*\rho g

\triangle P=1.95*10^{-4}

 

6 0
4 years ago
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