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At the Equator near Earth’s surface, the magnetic field is approximately 82.2 µT northward and the electric field is about 143 N

IrinaK [193]

Answer:

Magnitude of gravitational force of the electron= 3.74×10^12N

Explanation:

Felectron= Fgravitational

Therefore:

Felectron/Fgravitational = kq^2/r^2 ×(r^2/Gm^2)

= kq^2/Gm^2

Where G= gravitational constant

m = mass of electron=9.1×10^-31

K= 8.9x10^9

q= 1.6×10^-19

Magnitude of gravitational force= (8.9×10^9)×(1.6×10^-19)^2/(6.7×10^-11)×(9.1×10^-31)

=( 2.2784×10^-28) / ( 6.097×10^-41)

= 3.74×10^12N

7 0

3 years ago

You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.

Alja [10]

Answer:

Part a)

$M = 7.25 \times 10^{25} kg$

Part b)

$M = 2\times 10^{30} kg$

Explanation:

Part a)

As we know that the diameter of the planet is given as

$d = 1.8 \times 10^7 m$

now the radius of the planet is given as

$r = 9 \times 10^6 m$

now we know that the acceleration due to gravity of the planet is given by the equation

$g = \frac{GM}{r^2}$

here we know that

$g = 59.7 m/s^2$

now from above equation we have

$59.7 = \frac{(6.67 \times 10^{-11})M}{(9\times 10^6)^2}$

now we have

$M = 7.25 \times 10^{25} kg$

Part b)

Now by kepler's law we know that

time period of revolution of planet about the star is given as

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

so we have

$\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}$

now we have

$\frac{1^2}{402^2} = \frac{(1.5 \times 10^11)^3}{r^3}}$

$rr = 8.17 \times 10^{12} m$

mula of time period

$402\times (365\times 24 \times 3600) = 2\pi \sqrt{\frac{(8.17\times 10^12)^3}{(6.67\times 10^{-11})M}}$

Now we have

$M = 2\times 10^{30} kg$

7 0

3 years ago

A 25 kg child is bouncing on a trampoline, which can be treated as an ideal spring with spring constant 2900 N/m. If the trampol

White raven [17]

Answer:

Explanation:

Energy store in the compressed trampoline = potential energy of at the maximum height ignoring friction

energy stored in the trampoline = $\frac{1}{2} kx^{2}$ where k is spring constant and x is the distance compressed = 0.5 × 2900 × 0.38² = 209.38 J

209.38 J = 25 × 9.8 × h

h maximum height attain = 209.38 J / ( 25 × 9.8) = 0.855 m

5 0

3 years ago

Home heating systems usually work in the following way: When the furnace warms a house above the set temperature of the thermost

Paraphin [41]

Home heating systems work through negative feedback by regulating the temperature through thermostat.

<h3>How home heating systems work through negative feedback?</h3>

In thermostat, when the temperature of the room environment increases by the negative feedback system the furnace gets turn off, allowing the room to get to its normal temperature and when the temperature lower down it turns on again and maintain the temperature in equilibrium state.

So we can conclude that home heating systems work through negative feedback by regulating the temperature through thermostat.

Learn more about temperature here: brainly.com/question/24746268

#SPJ9

7 0

2 years ago

What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of 0.35

Kitty [74]

V=f*wavelength
30m/s=f*(0.35m)
f=85.7 Hz

5 0

3 years ago

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