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GenaCL600 [577]
2 years ago
14

Helllllllllllllllllp plss

Physics
1 answer:
andrey2020 [161]2 years ago
5 0

Answer:

I don't know answer. ssza

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Find the voltage drop (in volt) along a 93.4 meter long 10 gauge copper wire carrying acurrent of 72.5 A. The diameter of a 10 g
Sophie [7]

Answer: 5.41 V

Explanation:in order to explain this result we have to use the Ohm law given by:

ΔV=R*I where R is the resistance which is equal R= ρ*L/A . ρ is the resistivity, L the length of the wire and A is the cross section. I is the current.

Then we have

ΔV=ρ*L*I/A= 1.68 * 10^-8 Ωm*93.4 m*72.5A/2.1* 10^-5 m^2=5.41 V

3 0
3 years ago
Choose only one correct option. Explanation needed.
Mama L [17]

Answer:

\large \boxed{\mathrm{C. \  \  \frac{500}{7 \times 15  \times 8} \ g/cm^3 }}

Explanation:

\displaystyle \sf Density = \frac{mass}{volume}

\displaystyle \rho = \frac{m}{V}

\sf mass=500 \ g

\sf volume \ of \ a \ cuboid=width  \times length  \times height=( 7 \times 15 \times 8) \ cm^3

\displaystyle \rho = \frac{500}{7 \times 15  \times 8}

7 0
3 years ago
Which of these forces pull or push upward, and which pull or push downward? Explain.
PtichkaEL [24]

Answer:

A force is a push or pull that acts upon an object as a result of that objects interactions

Explanation:

8 0
3 years ago
A negative charge is at rest at the origin of an axis system. Location x is at coordinate point (2m,3m) while location y is at (
Sergeu [11.5K]
The magnitude of the E-field decreases as the square of the distance from the charge, just like gravity.

Location ' x ' is  √(2² + 3²) = √13 m  from the charge.

Location ' y ' is √ [ (-3)² + (-2)² ] = √13 m from the charge.

The magnitude of the E-field is the same at both locations.

The direction is also the same at both locations ... it points toward the origin.


5 0
3 years ago
Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. There is now a nega
devlian [24]

Answer: its negative

Explanation: becase it is

5 0
3 years ago
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