1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
murzikaleks [220]
3 years ago
10

You want to move a heavy box with mass 30.0 across a carpeted floor. You pull hard on one of the edges of the box at an angle 30

above the horizontal with a force of magnitude 240 , causing the box to move horizontally. The force of friction between the moving box and the floor has magnitude 41.5 . What is the box's acceleration just after it begins to move?
Find both the x and y components of the acceleration of the box.
Enter the x and y components of the acceleration in meters per second squared, separated by commas.

Physics
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:

Explanation:

Check attachment for solution

You might be interested in
A bullet B of mass mB traveling with a speed v0 = 1400 m/s ricochets off a fixed steel plate A of mass mA. Let mA ≫ mB so that i
Greeley [361]

Answer:

Rebounce angle is 345°

Rebounce speed is 989.95m/s

Explanation:

Calculate the x  component of the velocity of the bullet before impact by using the following relation:

Vbx= Vb Cos thetha

Here,  is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°

Substituting

Vbx = Cos15 ×1400 = 1352.30m/s

Calculate the y component using the relation:

Vby = Vo Sin theta

Vby = sin 15° × 1400

Vby = 362.35m/s

The rebounce angle = 360 - incidence angle

Rebounce angle =( 360 - 15)° = 345°

The rebound speed V' = Vby - Vbx

V' = (1352.30 - 362.35)m/s

V' = 989.95 m/s

5 0
3 years ago
A 795-loop square armature coil with a side of 10. 5 cm rotates at 70. 0 rev/s in a uniform magnetic field of strength 0. 45 t.
Agata [3.3K]

The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.

No. of loop = 795

Diameter of the coil = 10.5 cm

Radius of the coil = 5.25 cm

Magnetic Field, B = 0.45 T

Time, t = 70.0 rev/s

              V_{rms} =\frac{NwAB}{\sqrt{2} }

Where,

              N = No. of loop

              A = Area of the coil

              B = Magnetic Field

              V_{rms} = Voltage rms

Area of the coil = πr²

                        = 86.57 cm²

w = 2π/t

   =( 2 × 3.141)/70.0

   = 0.089

V_{rms} =\frac{795*0.089*86.57* 0.45}{\sqrt{2} }\\\\V_{rms} =\frac{2756.36}{\sqrt{2} }\\\\\\V_{rms} =\frac{2756.36}{1.414 }\\\\V_{rms} = 1.94 * 10^-^5 V

Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

Learn more about rms voltage here:

brainly.com/question/13156072

#SPJ4

8 0
9 months ago
Block B (of mass m) is initially at rest. Block A (of mass 3m) travels toward B with an initial speed v0 (vee nought) and collid
NeTakaya

Answer:

The maximum height reached by the two blocks is approximately 0.1147959 × v₀²

Explanation:

The mass of block B = m

The mass of block A = 3·m

The initial velocity of block B, v₂ = 0 m/s

The initial velocity of block A, v₁ = v₀

The amount of friction between the blocks and the surface = Negligible friction

By the Law of conservation of linear momentum, we have;

Total initial momentum = Total final momentum

3·m·v₁ + m·v₂ = (3·m + m)·v₃ = 4·m·v₃

Plugging in the values for the velocities gives;

3·m × v₀ + m × 0 = (3·m + m)·v₃ = 4·m·v₃

∴ 3·m × v₀ =  4·m·v₃

\therefore v_3 = \dfrac{3}{4} \times v_0 = 0.75 \times v_0

The kinetic energy, K.E. of the combined blocks after the collision is given as follows;

K.E. = 1/2 × mass × v²

\therefore K.E. = \dfrac{1}{2} \times 4\cdot m \times \left (\dfrac{3}{4} \cdot v_0 \right )^2 = \dfrac{9}{8} \cdot m\cdot v_0^2

The potential energy, P.E., gained by the two blocks at maximum height = The kinetic energy, K.E., of the two blocks before moving vertically upwards

The potential energy, P.E. = m·g·h

Where;

m = The mass of the object at the given height

g = The acceleration due to gravity

h = The height at which the object of mass, 'm', is located

Therefore, for h = The maximum height reached by the two blocks, we have;

P.E. = K.E.

m \cdot g \cdot h =  \dfrac{9}{8} \cdot m\cdot v_0^2

h = \dfrac{\dfrac{9}{8} \cdot m\cdot v_0^2}{m \cdot g }  = \dfrac{9}{8} \cdot \dfrac{ v_0^2}{ g }  =  \dfrac{9}{8} \cdot \dfrac{ v_0^2}{ 9.8} = \dfrac{42}{392} \cdot  v_0^2 \approx 0.1147959   \cdot  v_0^2

The maximum height reached by the two blocks, h ≈ 0.1147959·v₀².

7 0
2 years ago
Discuss how does a Van de Graaff generator works?​
Svetllana [295]

Answer:

How does a Van de Graaff generator works?

A Van de Graaff generator pulls electrons from the Earth, moves them along a belt and stores them on the large sphere. These electrons repel each other and try to get as far away from each other as possible, spreading out on the surface of the sphere. ... It provides a convenient path for electrons to move to the ground.

source-

scienceworld.ca

5 0
3 years ago
A force vector points due east and has a magnitude of 150 newtons. A second force is added to . The resultant of the two vectors
balandron [24]

Answer:

a. 240 N due east

b. 540 N due west

Explanation:

Let east be the reference direction

(a) if the resultant force has a magnitude of 390 N and points east, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of

390 - 150 = 240 N

(b) if the resultant force has a magnitude of 390 N and points west, it would be -390N is eastern reference, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of

-390 - 150 = -540 N

This force would point west

6 0
2 years ago
Other questions:
  • Work in the amount of 280 J is done in lifting an object a distance of 4.0 m in a time. How much force did it take to lift the o
    6·1 answer
  • A rocket sled for testing equipment under large accelerations starts at rest and accelerates according to the expression a = (3.
    5·1 answer
  • Two identical blocks are connected to opposite ends of a compressed spring. the blocks initially slide together on a frictionles
    5·1 answer
  • Which quantity does a light-year measure?<br>distance<br>speed<br>time<br>volume​
    6·2 answers
  • As mass increases what happens to the kinetic energy
    10·1 answer
  • Can anybody help me solve this problem? Thank you so much!
    6·1 answer
  • How can we magnetise a piece of iron.
    13·1 answer
  • Determine the magnitude of the force for each direction. A. Add the forces that are applied in the same direction. B. Subtract f
    6·1 answer
  • Who Henry Mosléy?!!!​
    8·1 answer
  • Which conditions are necessary for rain to form?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!