You want to move a heavy box with mass 30.0 across a carpeted floor. You pull hard on one of the edges of the box at an angle 30
above the horizontal with a force of magnitude 240 , causing the box to move horizontally. The force of friction between the moving box and the floor has magnitude 41.5 . What is the box's acceleration just after it begins to move?
Find both the x and y components of the acceleration of the box.
Enter the x and y components of the acceleration in meters per second squared, separated by commas.
Find both the x and y components of the acceleration of the box.
Enter the x and y components of the acceleration in meters per second squared, separated by commas.
1 answer:
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Answer:
(a) Friction force = 50 N
(b) Work done by friction = 300 j
(c) Net work done = 0 j
Explanation:
We have given that the box is pulled by 6 meter so d = 6 m
Force applied on the box F = 60 N
We have have given that velocity is constant so acceleration will be zero
So to applied force will be utilized in balancing the friction force
So friction force
Work done by friction force
Work done by applied force
So net work done = 300-300 = 0 j
Answer:
the two vehicles will be moving at a speed of 6.16 m/s
Explanation:
This is a case of completely inelastic collision, therefore, the conservation of momentum can be written as:
which given the information provided results into: