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murzikaleks [220]
3 years ago
10

You want to move a heavy box with mass 30.0 across a carpeted floor. You pull hard on one of the edges of the box at an angle 30

above the horizontal with a force of magnitude 240 , causing the box to move horizontally. The force of friction between the moving box and the floor has magnitude 41.5 . What is the box's acceleration just after it begins to move?
Find both the x and y components of the acceleration of the box.
Enter the x and y components of the acceleration in meters per second squared, separated by commas.

Physics
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:

Explanation:

Check attachment for solution

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Umnica [9.8K]

this question is true

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4 years ago
A rod 7.0 m long is pivoted at a point 2.0 m from the left end. A downward force of 50 N acts at the left end, and a downward fo
kicyunya [14]

If the rod is in rotational equilibrium, then the net torques acting on it is zero:

∑ τ = 0

Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:

• at the left end,

τ = + (50 N) (2.0 m) = 100 N•m

• at the right end,

τ = - (200 N) (5.0 m) = - 1000 N•m

• at a point a distance d to the right of the pivot point,

τ = + (300 N) d

Then

∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0

⇒   (300 N) d = 1100 N•m

⇒   d ≈ 3.7 m

6 0
2 years ago
Attempt 3 of 2
Wewaii [24]

Answer:

mass.

Explanation:

other physical factors are changeable but the mass of a particular substance is always constant.

6 0
3 years ago
2. An egg rolls off the kitchen counter with a velocity of 4m/s. If
-Dominant- [34]

Answer:

800m/s

Explanation:

6 0
3 years ago
Calculate the amount of heat (in kJ) required to convert 97.6 g of water to steam at 100° C. (The molar heat of vaporization of
Ratling [72]

Answer:

221.17 kJ

Explanation: Note the heat of vaporization is in kJ/mol,then to determine the number of moles of water: divide the mass by 18. Then multiply the number of moles by the molar heat of vaporization of water.

N = 97.6 ÷ 18

Q=molar heat *moles

Q = (40.79) * (97.6 ÷ 18)

This is approximately 221.17 kJ

4 0
3 years ago
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