You want to move a heavy box with mass 30.0 across a carpeted floor. You pull hard on one of the edges of the box at an angle 30
above the horizontal with a force of magnitude 240 , causing the box to move horizontally. The force of friction between the moving box and the floor has magnitude 41.5 . What is the box's acceleration just after it begins to move?
Find both the x and y components of the acceleration of the box.
Enter the x and y components of the acceleration in meters per second squared, separated by commas.
Find both the x and y components of the acceleration of the box.
Enter the x and y components of the acceleration in meters per second squared, separated by commas.
1 answer:
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Answer:
See the answers below.
Explanation:
to solve this problem we must make a free body diagram, with the forces acting on the metal rod.
i)
The center of gravity of the rod is concentrated in half the distance, that is, from the end of the bar to the center there is 40 [cm]. This can be seen in the attached free body diagram.
We have only two equilibrium equations, a summation of forces on the Y-axis equal to zero, and a summation of moments on any point equal to zero.
For the summation of forces we will take the forces upwards as positive and the negative forces downwards.
ΣF = 0
Now we perform a sum of moments equal to zero around the point of attachment of the string with the metal bar. Let's take as a positive the moment of the force that rotates the metal bar counterclockwise.
ii) In the free body diagram we can see that the force acts at 18 [cm] of the string.
ΣM = 0
