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ira [324]
2 years ago
10

I need help with question 48

Chemistry
1 answer:
Stells [14]2 years ago
6 0

Answer:

V H2SO4=30 ml=0.03 l

Cm=16M

CM=n/V

n=CM×V

n= 0.48 moles H2SO4

Cm=0.48/0.3

CM=1.6M

Answer B

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Identify each section of the periodic table.<br><br> metals<br> nonmetals<br> metalloids
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Answer:

i added this table for some help

Explanation:

here are some examples

<u>metals:</u>They are hard and shiny, strong, and easy to shape. They are used for many industrial purposes. This group includes iron, gold, silver, chromium, nickel, and copper, some of which are also noble metals.

<u>non-metals:</u>a chemical element (as boron, carbon, or nitrogen) that lacks the characteristics of a metal and that is able to form anions, acidic oxides, acids, and stable compounds with hydrogen.

<u>metalloids:</u>Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor. Metalloids have mixed properties which are difficult to characterize.

8 0
3 years ago
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Explanation:

The Formula for Kinetic Energy is KE = 0.5 x mv², using this equation you can then find the item with the most Kinetic Energy in Joules (J) 0.5 x 20 x 10 = 200 Joules.

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3 years ago
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The soil of an agricultural field is too basic what can we do to correct it
katen-ka-za [31]

Answer:

you can correct it by adding an acid to make it neutral or less basic

3 0
3 years ago
The pathway by which carbon is transferred from living organisms to the atmosphere is called:
Phoenix [80]

Answer:

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Explanation:

All exergonic processes produced in the cell, through which substances oxidize and chemical energy is released, are grouped under the name of cellular respiration, but to break down an organic molecule the cells employ, mainly dehydrogenations that can be carried carried out in the presence or absence of atmospheric O2 oxygen. There are therefore two types of breathing: aerobic respiration and anaerobic respiration. The latter also called fermentation.

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Calculate the concentration imports per million ppm of DDT if a sample size of 5000 g contained 0.10 g DDT
nevsk [136]

Answer:

20ppm

Explanation:

parts per million are defined as the mass of solute in mg (In this case, mass of DDT) per kg of sample.

To solve this question we must find the mass of DDT in mg and the mass of sample in kg:

<em>Mass DDT:</em>

0.10g * (1000mg / 1g) = 100mg

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5000g * (1kg / 1000g) = 5kg

Parts per Million:

100mg / 5kg =

<h3>20ppm</h3>
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