3 years ago

How many electron are in the outer shell of an neutral atom of 14 atomic number

Chemistry

1 answer:

Anon25 [30]3 years ago

5 0

I think there is 4 electrons in the outer shell of 14 atomic number. If I'm wrong, know that I'm not very good.

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$H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}$

Explanation:

Hello there!

In this case, since perchloric acid is HClO4 and is a strong acid and calcium hypochlorite is Ca(ClO)2, the undergoing molecular chemical reaction turns out:

$2HClO_4{(aq)}+Ca(ClO)_2{(aq)}\rightarrow 2HClO{(aq)}+Ca(ClO_4)_2{(aq)}$

Thus, since the resulting hypochlorous acid is weak, it does not fully ionize, so it remains unionized, however, we can write the ions for the other species:

$2H^++2(ClO_4)^-+Ca^{2+}+2(ClO)^-\rightarrow 2HClO{(aq)}+Ca^{2+}+2(ClO_4)^-$

Now, we can cancel out the spectator ions, calcium and perchlorate, to obtain:

$2H^+(aq)+2(ClO)^-(aq)\rightarrow 2HClO{(aq)}\\\\H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}$

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