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Elden [556K]
3 years ago
11

In each reaction box, place the best reagent and conditions from the list below.

Chemistry
1 answer:
Serggg [28]3 years ago
8 0
This is a two step step reaction as shown below,

Step 1:
           Epoxidation of Alkene:
                                              In first step Cyclohexene is treated with peroxybenzoic acid in the presence of Dichloromethane which results in the formation of epoxide moiety.

Step 2:
           Nucleophillic Substitution Reaction:
                                                                  In second step the epoxide formed is treated with Sodium Methoxide which acts as a nucleophile and attacks the less hindered carbon of epoxide resulting in the formation of final product as shown below.

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Carbon tetrachloride, CCl4, once used as a cleaning fluid and as a fire extinguisher, is produced by heating methane and chlorin
Elena-2011 [213]

Answer:

1.882 g

Explanation:

Data Given

mass of Cl₂ = 33.4 g

mass of CH₄ = ?

Reaction Given:

                       CH₄+ 4Cl₂ --------→ CCl₄ + HCl

Solution:

First find the mass of CH₄ from the reaction that it combine with how many grams of Chlorin.

Look at the balanced reaction

                    CH₄     +     4Cl₂ --------→ CCl₄ + 4HCl

                    1 mol        4 mol

So 1 mole of CH₄ combine with 4 moles of Cl₂

Now

convert the moles into mass for which we have to know molar mass of CH₄ and Cl₂

Molar mass of Cl₂ = 2 (35.5)

Molar mass of  Cl₂  = 71 g/mol

mass of Cl₂

                mass in grams = no. of moles x molar mass

                mass of Cl₂ = 4 mol x 71 g/mol

                mass of Cl₂  = 284 g

Molar mass of CH₄= 12+ 4(1)

Molar mass of CH₄= 16 g/mol

mass of CH₄

                mass in grams = no. of moles x molar mass

                mass of CH₄= 1 mol x 16 g/mol

                mass of CH₄ = 16 g

So,

284 g of Cl₂  combine with 16 g of methane ( CH₄ ) then how many grams of CH₄ is needed to combine with 33.4 g of Cl₂  

Apply unity Formula

                           284 g of Cl₂  ≅ 16 g of methane ( CH₄ )

                           33.4 g of Cl₂  ≅ X g of methane ( CH₄ )

By cross multiplication

                          X g of methane ( CH₄ ) = 16 g x 33.4 g / 284 g

                          X g of methane ( CH₄ ) = 1.88 g

1.882 g of methane (CH₄) will needed to combine with 33.4 g of Cl₂

So

methane (CH₄) = 1.882 g

5 0
3 years ago
Which of the following are interactions between particles in a liquid?
Artemon [7]
Can you pick more than one?
8 0
3 years ago
Describe why corrosion is a natural process
Sladkaya [172]

<u>Answer :</u>

  • <u>Answer :because it happens due to moisture and oxygen </u>

6 0
3 years ago
Is there a clear difference between a very polar covalent bond and an ionic bond explain?
garik1379 [7]
Yes, Ionic bonds do not share electrons. Polar covalent bonds share electrons they just share them unevenly due to the polarity.
4 0
3 years ago
A strong acid, HA, is added to water. Which statement about the solution is true?
Arturiano [62]
My answer to this question is C

3 0
3 years ago
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