Question

The horizontal surface on which the block slides is frictionless. If F = 20 N and M = 5.0 kg, what is the magnitude of the resulting acceleration of the block?

Answer 1

Answer:

$a=4m/s^2$

Explanation:

Using Newton's second law:

$F=ma$

Where $F$ is the force applied on the object, $m$ is the mass of the object, and $a$ is the acceleration.

In this case we need the acceleration, so we clear for $a$:

$a=\frac{F}{m}$

we know that the force is: $F=20N$, and the mass: $m=5kg$

so the acceleration:

$a=\frac{20N}{5kg}$

$a=4m/s^2$

the acceleration of the block is: $a=4m/s^2$