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elena55 [62]
3 years ago
12

What 2 types of rock are most common beneath Earth’s crust?*

Chemistry
1 answer:
lora16 [44]3 years ago
4 0
A and C, Igneous and Metamorphic
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PLSSS HELP. And there’s also at the bottom of the picture another option if u didn’t see it
WARRIOR [948]

Answer:

B. Gradualism

Explanation:

8 0
3 years ago
Calculate the heat energy required to melt 4kg of ice when the specific latent heat of fusion of water is 334,000 J/kg.
Setler79 [48]

Taking into account the definition of calorimetry and latent heat, the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat energy required to melt ice</h3>

In this case, you know:

  • m= 4 kg
  • L= specific latent heat of fusion of water= 334,000 \frac{J}{kg}

Replacing in the expression for latent heat:

Q = 4 kg× 334,000 \frac{J}{kg}

Solving:

<u><em>Q= 1,336,000 J= 1,336 kJ </em></u>(being 1,000 J= 1 kJ)

Finally, the correct answer is the first option: the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 \frac{J}{kg} is 1,336 kJ.

Learn more about calorimetry:

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7 0
2 years ago
Read 2 more answers
What would the corresponding
ad-work [718]

Answer:

7,9,11

Explanation:

this is because water includes 0H, which would mean that it is more than 6

4 0
1 year ago
A compound containing only carbon, nitrogen, and hydrogen is analyzed to contain 58.82% carbon, 27.45% nitrogen, and 13.73% hydr
Mekhanik [1.2K]
When given percents for an empirical formula problem, first consider all the percents as grams.

58.82% carbon —> 58.82 g carbon
27.45% nitrogen —> 27.45 g nitrogen
13.73% hydrogen —> 13.73 g hydrogen

Then convert the grams of all the elements to moles, based on their molar masses.

Carbon - 58.82 g / 12.01 g/mol = 4.898 mol carbon

Nitrogen - 27.45 g / 14.01 g/mol = 1.959 mol nitrogen

Hydrogen - 13.73 g / 1.008 g/mol = 13.62 mol hydrogen

Then divide all of the mole numbers by the smallest number of moles, which is in this case, the 1.959 mol of nitrogen.

Carbon - 4.898 / 1.959 = 2.5

Nitrogen - 1.959 / 1.959 = 1

Hydrogen - 13.62 / 1.959 = 7

You want whole numbers for all of your mole numbers, so multiply all of them by 2, since 2.5 isn’t a whole number.

Final answer: C5N2H14
4 0
3 years ago
Ethene is the first member of the
FrozenT [24]
The answer is (b.) alkyne series.
8 0
3 years ago
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