What 2 types of rock are most common beneath Earth’s crust?*

Mountain ranges are formed by: plate collision melting of rock in the mantle evaporation of ocean waters buildup of salt and sed

Likurg_2 [28]

Mountain ranges are caused by "A) Plate Collision"

6 0

3 years ago

Read 2 more answers

What process is aided by lightning legumes and soul bacteria

g100num [7]

so this is right answer

For reasons that are unclear, no eukaryotic enzymes can break the triple bond of N2. The reduction of N2 to NH3 (nitrogen fixation) is limited to prokaryotes and is catalysed by nitrogenase. Since most of the nitrogen entering the biosphere (around 100 million metric tonnes of N2 per annum) does so through nitrogenase activity (lightning contributes about 10%), those plants that associate with nitrogen-fixing bacteria have a significant selective advantage under conditions of limiting nitrogen.

8 0

3 years ago

1 ) your favorite recipe for preparing 100 brownies requires the following : 6 eggs , 5 cups flour and 2 sticks of butter . how

erastova [34]

If 100 brownies require 6 eggs, 5 cups of flour, and 2 sticks of butter. Then, 50 brownies should require half of those required to make 100 brownies. Use ratio and proportion to determine the number of eggs needed:

100/50 = 6/x
x = 3

3 0

3 years ago

Wastewater discharged into a stream by a sugar refinery contains 3.40 g of sucrose (C12H22O11) per liter. A government-industry

Ipatiy [6.2K]

Answer: The pressure that must be applied to the apparatus is 0.239 atm

Explanation:

To calculate the osmotic pressure, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

or,

$\pi=i\times \frac{m_{solute}}{M_{solute}\times V_{solution}\text{ (in L)}}}\times RT$

where,

$\pi$ = osmotic pressure of the solution

i = Van't hoff factor = 1 (for non-electrolytes)

$m_{solute}$ = mass of sucrose = 3.40 g

$M_{solute}$ = molar mass of sucrose = 342.3 g/mol

$V_{solution}$ = Volume of solution = 1 L

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $20^oC=[20+273]K=293K$

Putting values in above equation, we get:

$\pi =1\times \frac{3.40g}{342.3g/mol\times 1}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 293K\\\\\pi =0.239atm$

Hence, the pressure that must be applied to the apparatus is 0.239 atm

3 0

3 years ago

Select the correct hybridization for the central atom based on the electron geometry cocl2 (carbon is the central atom).

Rainbow [258]

In this compound (Phosgene) the central atom (carbon is Sp² Hybridized).

Sp, Sp² and Sp³ can be calculated very simply by doing three steps,

Step 1:
Assume triple bond and double bond as one bond and assign s or p to it. In this example carbon double bond oxygen is considered once and let suppose it is s. Now we are having our s.

Step 2:
Count lone pair of electron, each lone pair counts for s and p. In this case there is no lone pair of electron on carbon, so not included.

Step 3:
Count single bonds for s and p. As we have already assigned s to the double bond, now one p for one single bond, and other p for the other single bond.

Result:
So, we counted 1 s for double bond, 1 p for one single and other p for second single bond. As a whole we got,

Sp²

Practice:
You can practice for hybridization of Oxygen in this molecule. Oxygen has 2 lone pair of electrons. (Hint: Sp² Hybridization)

7 0

2 years ago