I believe the correct response would be D. At least 2 of the above statements are correct.
<span>There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.
1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst.
4. Reduce pressure way below the limit 269 kPa.</span>
Answer:
Hi.. U should do like this
Cu + S - - - >Cu2S
Explanation:
the enerfy of of one photon of this light is 4.85x10^-19 J
<h2>E= 6.63 x 10^-34 J/S x 7.32 x10^14 S ^-1</h2>
E= 4.85x10^-19 J
