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Jobisdone [24]
4 years ago
12

Atoms of different elements have a different mass and volume. Why is the statement true?

Chemistry
2 answers:
irina [24]4 years ago
8 0

Answer:

different elements have different number of electrons and shells/orbits thatswhy it have different atomic mass and size.

Explanation:

Crazy boy [7]4 years ago
6 0

The answer is D.) Atoms have unique properties that define them.

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Which part of an atom is mostly empty space?
Brilliant_brown [7]
I’m pretty sure it’s B

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3 years ago
Which statement describes solstices?
RSB [31]

Answer:

Option A (They happen as the Sun hits its maximum and minimum level throughout the sky) is the correct option.

Explanation:

  • Solstice seems to be the moment whereas at noon this same sun achieved its maximum as well as minimum position, actually results throughout the year's shortest as well as biggest days.  
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Some other options given should not be in accordance with the given context. So, the correct approach would've been option A.

7 0
3 years ago
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Unsweetened chocolate has a very bitter taste. What does this taste indicate about
Free_Kalibri [48]

Answer:

C. They are basic

8 0
3 years ago
What reaction type is MgCl2 ---> Mg + Cl2 ?
Firlakuza [10]

Answer:

A.Synthesis

Explanation:

What reaction type is MgCl2 ---> Mg + Cl2 ?

a. Synthesis

b. Single Replacement

c. Double Replacement

d. Decomposition

Answer

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7 0
3 years ago
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Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrange
lara31 [8.8K]

Answer:

-) 2-methylbut-2-ene

-) 2-methylbut-1-ene

-) 3-methylbut-1-ene

Explanation:

in this case, the hydration of alkenes is a <u>marknovnikov reaction</u>, this means that the "OH" group would be added in the <u>most substituted carbon</u> of the double bond. (Figure 1)

For 2-methylbut-2-ene the most substituted carbon is the <u>tertiary carbon</u> (the carbon in the right of the double bond), so we will obtain the desired molecule. In 2-methylbut-1-ene the most substituted carbon is again the <u>tertiary carbon</u> (the carbon in the bottom of the double bond), so we will obtain 2-methyl-2-butanol. Finally, for 3-methylbut-1-ene the carbocation would be formed on carbon 3, this is a secondary carbocation. We can obtain a most stable carbocation if we do a <u>hydride shift</u> (Figure 2). With this new molecule is possible to obtain 3-methylbut-1-ene.

6 0
4 years ago
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