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3 years ago

What is the inheritance pattern for the blood type genes- A,B,O?

2 answers:

8 0

It's carried out by a sugar "i", it can be dominant (Homozygous, Heterozygous) & recessive. A & B are co-dominant to each other whereas O is recessive to both of them.

Hope this helps!

aniked [119]3 years ago

7 0

<span>Individuals with type O blood do not produce ABO antigens. Therefore, their blood normally will not be rejected when it is given to others with different ABO types. As a result, type O people are universal donors for transfusions, but they can receive only type O blood themselves. Those who have type AB blood do not make any ABO antibodies. Their blood does not discriminate against any other ABO type. Consequently, they are universal receivers for transfusions, but their blood will be agglutinated when given to people with every other type because they produce both kinds of antigens.</span>

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The chemical equation given below represents the chemical reaction between lithium (Li) and sulfur (S). In the equation, why is

algol [13]

Answer:

A. to show the number of lithium atoms involved in the reaction

Explanation:

The reaction between lithium and sulfur produces lithium sulfide where two lithium and one sulfur atoms react.

Balanced equation: 2 Li + S = Li2S

The 2 present before Li on the reactant's side shows how many lithium atoms are supposed to be present per every 1 sulfur atom for this reaction to be balanced and true.

That is it! :)

5 0

4 years ago

Read 2 more answers

what is the molecular formula of benzoyl peroxide (c7h5o2) of the molecular mass is 0.242 kg/mol?(show work please)

AfilCa [17]

Answer : The molecular formula of benzoyl peroxide is $C_{14}H_{10}O_4$

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

As we are given that the molar mass of compound is, 0.242 kg/mol.

Molecular mass = 0.242 kg/mol = 242 g/mol (1 kg = 1000 g)

The empirical mass of $C_7H_5O_2$ = 7(12) + 5(1) + 2(16) = 121 g/eq

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

$n=\frac{242}{121}$

$n=2$

Molecular formula = $(C_7H_5O_2)_n$ = $(C_7H_5O_2)_2$ = $C_{14}H_{10}O_4$

Thus, the molecular formula of benzoyl peroxide is $C_{14}H_{10}O_4$

6 0

3 years ago

Explain organic chemistry

monitta

Explanation:

The study of the structure, properties, composition, reactions, and preparation of carbon-containing compounds

8 0

3 years ago

Read 2 more answers

A solution contains some or all of the ions Cu²⁺, Al³⁺, K⁺, Ca²⁺, Ba²⁺, Pb²⁺, and NH₄⁺. The following tests were performed, in o

Nina [5.8K]

Answer:

Among given, the ions which are present in the given solution are:

Cu²⁺, Al³⁺ and K⁺

Among given, the ions which are absent in the given solution are:

Pb²⁺, Ca²⁺ and Ba²⁺

The ion which no conclusion is NH₄⁺.

Explanation:

Reagents given are used in salt analysis. The salt analysis is a qualitative analysis used for the identification of cations and anions of inorganic salts.

HCl is used for the identification of group I cations. As no reaction occurred when HCl is added to the solution, that means group I cations are absent.

So, among the given Pb²⁺ is a group I cation, therefore, Pb²⁺ is absent.

H₂S along with HCl is used for the identification group II salts.

Addition of Addition of H₂S with 0.2 M HCl produced a black solid, so, group II cation Cu²⁺ is present.

H₂S is used for the identification of group III cations.

When H₂S is added to the filtrate of group II, white precipitate is formed that means group III cations are present. Among group III cations, Al³⁺ is present.

Addition of (NH₄)₂HPO₄ in the presence of NH₃ is used for the identification of group IV cations.

As no precipitate is formed, therefore, group IV cations are absent.

So among given options, Ca²⁺ and Ba²⁺ are absent in the given solution.

The final supernatant when heated produces purple flame which indicates the presence of K⁺.

Therefore, among given, the ions which are present in the given solution are:

Cu²⁺, Al³⁺ and K⁺

Among given, the ions which are absent in the given solution are:

Pb²⁺, Ca²⁺ and Ba²⁺

The ion which no conclusion is NH₄⁺.

5 0

3 years ago

Grignard reactions are highly exothermic and are performed in ether solvent. There is a real risk of fire during this reaction.

AleksAgata [21]

Answer:

Ideally, extinguish the flames with a glass watch or beaker.

Explanation:

When you cover the distillation equipment with a watch glass or beaker, you reduce the oxygen content and it is completely eliminated thanks to the fire itself that consumes it. Once there is no more oxygen the fire is extinguished and it should take no more than 2 or 3 seconds to occur this situation

It is the easiest and most careful way to extinguish the fire during the Grignard reaction

8 0

4 years ago