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3 years ago

Give an example of something you could do to reduce friction.

Physics

2 answers:

Archy [21]3 years ago

5 0

Put oil on a table, that would reduce friction

stich3 [128]3 years ago

4 0

Answer:

There are a number of ways to reduce friction:

Rough surfaces produce more friction and smooth surfaces reduce friction. Lubrication is another way to make a surface smoother. ... Reduce the forces acting on the surfaces. Reduce the contact between the surfaces.

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How much power does it take to lift 70.0 N to 5.0 m high in 5.00 s?

lesantik [10]

Answer:

Power = 70 W

Explanation:

Given that,

Force, F = 70 N

Height, h = 5 m

Time, t = 5 s

We need to find the power of the object. We know that,

Power = work done/time

Put all the values,

$P=\dfrac{Fd}{t}\\\\P=\dfrac{70\times 5}{5}\\\\P=70\ W$

So, the required power is 70 W.

3 0

3 years ago

Mention & reasons why the ability to adapt to change is

s2008m [1.1K]

Answer:

The ability to adapt is important because :

1) It helps in the survival of human beings.

2) It brings more variation to the human kind.

3) It helps the species from getting endangered or extinct.

4) It brings transformation in the adapting kind.

Hope this helps you☺️☺️

5 0

3 years ago

Interactive LearningWare 10.1 reviews the concepts involved in this problem. A spring stretches by 0.0161 m when a 3.74-kg objec

yKpoI14uk [10]

Answer:

m = 3.91 kg

Explanation:

Given that,

Mass of the object, m = 3.74 kg

Stretching in the spring, x = 0.0161 m

The frequency of vibration, f = 3.84 Hz

When the object is suspended, the gravitational force is balanced by the spring force as :

$mg=kx$

$k=\dfrac{mg}{x}$

$k=\dfrac{3.74\times 9.8}{0.0161}$

k = 2276.52 N/m

The frequency of vibration is given by :

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

$m=\dfrac{k}{4\pi^2f^2}$

$m=\dfrac{2276.52}{4\pi^2\times (3.84)^2}$

m = 3.91 kg

So, the mass of the object is 3.91 kg. Hence, this is the required solution.

8 0

3 years ago

A speaker vibrates at a frequency of 200 hz what is its period

Norma-Jean [14]

Period = (1) / (frequency)

Period = (1) / (200 per second) = 0.005 second = 5 milliseconds

5 0

3 years ago

Read 2 more answers

Please answer correctly. <br>helppp plzzz<br>Urgent!!!!

Ksenya-84 [330]

Answer:

Gamma rays are mostly used in the radiotherapy/ radiooncology to treat cancer. They can also be used to spot tumours. Gamma rays can kill living cells and damage malignant tumor

3 0

3 years ago