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WINSTONCH [101]

2 years ago

11

Give an example of something you could do to reduce friction.

2 answers:

Archy [21]2 years ago

5 0

Put oil on a table, that would reduce friction

stich3 [128]2 years ago

4 0

Answer:

There are a number of ways to reduce friction:

Rough surfaces produce more friction and smooth surfaces reduce friction. Lubrication is another way to make a surface smoother. ... Reduce the forces acting on the surfaces. Reduce the contact between the surfaces.

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The reacting force that is equal to and opposite in the direction to the centripetal force and tends to fling air out of the cen

BARSIC [14]

Answer:

Centrifugal force

Explanation:

The reacting force that is equal to and opposite in the direction to the centripetal force and tends to fling air out of the center of rotation of High and Low pressure systems is called centrifugal force.

Centrifugal force is force that causes an object moving in a circular path to move out and away from the center of it's path, it always centripetal force and the force is imaginary, which can only be felt and not seen.

7 0

2 years ago

A submarine is 2.99 ✕ 102 m horizontally from shore and 1.00 ✕ 102 m beneath the surface of the water. A laser beam is sent from

Vsevolod [243]

Answer:

a The diagram of the situation is shown on the first uploaded image

b the angle of incidence beam striking the water is $\theta = 49.63^o$

c the angle of refraction beam striking the water is $r = 59.7^o$

d The angle the refracted beam make with respect to the horizontal is $= 30.3^o$

e The height of the target above sea level is

$h= 125.05m$

Explanation:

From the diagram we see that the angle of the beam striking the water is

$tan \theta = \frac{100}{85}$

$\theta = tan^{-1}(\frac{100}{85} )$

$= 49.63^o$

According to Snell's law

$\mu_{water} *sin(i) = \mu_{air} *sin(r)$

Where $\mu_{water }$ is the refractive index of water = 1.333

$i$ is the angle of incidence

$\mu_{air}$ is the refractive index of air = 1

r is the angle of refraction

Substituting values accordingly

$1.33 * sin (40.37) = 1 * sin(r)$

Making r the subject of the formula

$r = sin^{-1}(\frac{1.333 *sin(40.37)}{1})$

$= 59.7^o$

looking at the diagram we can see that to obtain the angle the refraction beam makes with the horizontal by subtracting the angle refraction from 90°

i.e $90 -59.7 = 30.3$ °

From the diagram we see that the height target above sea level can be obtained by this relation

$tan \theta = \frac{h}{214}\\$

Where h is the is the height

$tan(30.3) = \frac{h}{214}$

$h = 214 * tan (30.3)$

$=125.05m$

4 0

2 years ago

Why is it that when opening a tin milk, have to open two holes?

Oksi-84 [34.3K]

Answer:

so your milk is secured

Explanation:

8 0

2 years ago

wo small containers have a mass of 2.6 g each; one contains 2.4 g of water, the other 1.8 g of alcohol. If the alcohol is poured

vlada-n [284]

Answer:

5.6kg

Explanation:

4 0

2 years ago

Which statement about electrons and atomic orbitals is not true?

Lubov Fominskaja [6]

An electron cloud represents all the orbitals in an atom.

5 0

2 years ago

Read 2 more answers