Answer:
Observed time, t = 5.58 s
Explanation:
Given that,
Speed of light in a vacuum has the hypothetical value of, c = 18 m/s
Speed of car, v = 14 m/s along a straight road.
A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s.
We need to find the time the driver of the car measure for his trip between the poles. The relation between real and observed time is given by :
t is observed time.
So, the time observed by the driver of the car measure for his trip between the poles is 5.58 seconds.
Answer:
3 820 885 N
Explanation:
Gravitational equation
F = G m1 m2 / r^2
G = gravitational constant = 6.6713 x 10^-11 m^3/kg-s^2
F = 6.6713 x 10^-11 * 4.41 x 10^5 * 5.97 x 10^24 / ( 6.78x 10^6)^2
= 3820885 .3 N
Answer:
- 1.3 x 10⁻¹⁵ C/m
Explanation:
Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C
r = Radius of the arc = 5.30 cm = 0.053 m
θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad (Since 1 deg = 0.0175 rad)
L = length of the arc
length of the arc is given as
L = r θ
L = (0.053) (0.84)
L = 0.045 m
λ = Linear charge density
Linear charge density is given as
Inserting the values
λ = - 1.3 x 10⁻¹⁵ C/m
<span>79.75m/s .................................</span>
