The strength of the electric field is 5 N/C
Explanation:
The magnitude of the electric field produced by a single-point charge is given by:
where
is the Coulomb's constant
Q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
is the charge producing the field
r = 100 m is the distance from the charge at which we want to calculate the field
Substituting into the equation, we find the s trength of the electric field:
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Answer:
Δe=0.578 kJ/kg
Explanation:
Given data
Velocity v₁=0 m/s
Velocity v₂=34 m/s
to find
Specific energy change Δe
Solution
The specific energy change is simply determined from change in velocity
Δe=(v₂²-v₁²)/2
Put the given values to find the specific energy change
Δe=0.578 kJ/kg
Answer:
Explanation:
From the question we are told that
The number of turns is
The radius is
The position from the center consider is x = 3.45 cm = 0.0345 m
The induced emf is
Generally according to Gauss law
=>
Where A is the cross-sectional area of the solenoid which is mathematically represented as
=>
=> ggl;
Here is the permeability of free space with value
=>
=>